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Solve for b· iC = 0 - V= 20 ( I M = 20 (1 - 22 G = O C400 ik x = 40 n 1 = 2 0 ( 9 = 15 - l) n x G900 402 6400, if × = 80 y= 20 (1 - 800 ) 8021

Solve for b· iC = 0 - V= 20 ( I M = 20 (1 - 22 G = O C400 ik x = 40 n 1 = 2 0 ( 9 = 15 - l) n x G900 402 6400, if × = 80 y= 20 (1 - 800 ) 8021

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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ⒸSolution: Solve for y: if x = 0 y = 20 (1 - 8200) y = 20 (1 - 6400) y=0₂₁₂ if x=40 y = 20/1 - 90²1 6400, y=15 if x=80 y = 20 (1 80²) 14 60400 y = 0/1/ if x= 120 l' G400 Solve for dy dx if x=0 Solve for Ox = tan²1 (dy) = 0-40x 6400 y' -40 (0) 6400 if x = 40 y' = -40 (40) 6400 y' = 250x 10-3 ifx = 80 y'= -40 (80) 6400 y = 20 y=-25/1 Solve for ²y = -16=-6-25×10-3 dx² y₁ = - if x = 120 1=-500 × 10-3 tan (0)=0 tan (250x10³)-14-03 tan-(-500+10-3)= -26.56% 2/1/ y' = 40x120 6400 y² = -700x10³/ CENA Solve for P = (1 + (y') ²) 3/₂ -6.25x10-3 P if y'= 0 P= (1 + (0)²) ³/₂ -6.25×10-3 P= - 160/ if y'= -250x103 P= (1 + (250×10-3) 2) ³/2 -6-25x10-3 p=-176-23/ If y'= -500x10-3 1 = (1 + (-500 × 10-5) ²) ³/2 p= -6-25x10-3 P=-223.60 tan (150x109 = -36.86% if y'= -750x103 P= (1 + (-750 × 10-3)²) ³/2 -6.25x10-3 p=-2312.5 C
Transcribed Image Text:ⒸSolution: Solve for y: if x = 0 y = 20 (1 - 8200) y = 20 (1 - 6400) y=0₂₁₂ if x=40 y = 20/1 - 90²1 6400, y=15 if x=80 y = 20 (1 80²) 14 60400 y = 0/1/ if x= 120 l' G400 Solve for dy dx if x=0 Solve for Ox = tan²1 (dy) = 0-40x 6400 y' -40 (0) 6400 if x = 40 y' = -40 (40) 6400 y' = 250x 10-3 ifx = 80 y'= -40 (80) 6400 y = 20 y=-25/1 Solve for ²y = -16=-6-25×10-3 dx² y₁ = - if x = 120 1=-500 × 10-3 tan (0)=0 tan (250x10³)-14-03 tan-(-500+10-3)= -26.56% 2/1/ y' = 40x120 6400 y² = -700x10³/ CENA Solve for P = (1 + (y') ²) 3/₂ -6.25x10-3 P if y'= 0 P= (1 + (0)²) ³/₂ -6.25×10-3 P= - 160/ if y'= -250x103 P= (1 + (250×10-3) 2) ³/2 -6-25x10-3 p=-176-23/ If y'= -500x10-3 1 = (1 + (-500 × 10-5) ²) ³/2 p= -6-25x10-3 P=-223.60 tan (150x109 = -36.86% if y'= -750x103 P= (1 + (-750 × 10-3)²) ³/2 -6.25x10-3 p=-2312.5 C
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