Solve each triangle ABC that exists. A = 37° a = 3.3 c= 15.3 ... Select the correct choice below and, if necessary, fill in the answer boxes within the choice. A. There are two possible solutions for the triangle. The measurements for the solution with the longer side b are as follows. B, = C, =° b, = The measurements for the solution with the shorter side b are as follows. B, = (Round to the nearest tenth as needed.) C2 =| b2 = B. There is only one possible solution for the triangle. The measurements for the remaining angles B and C and side b are as follows. C= b= (Round to the nearest tenth as needed.) OC. There are no possible solutions for the triangle.
Solve each triangle ABC that exists. A = 37° a = 3.3 c= 15.3 ... Select the correct choice below and, if necessary, fill in the answer boxes within the choice. A. There are two possible solutions for the triangle. The measurements for the solution with the longer side b are as follows. B, = C, =° b, = The measurements for the solution with the shorter side b are as follows. B, = (Round to the nearest tenth as needed.) C2 =| b2 = B. There is only one possible solution for the triangle. The measurements for the remaining angles B and C and side b are as follows. C= b= (Round to the nearest tenth as needed.) OC. There are no possible solutions for the triangle.
Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE:
1. Give the measures of the complement and the supplement of an angle measuring 35°.
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Transcribed Image Text:Solve each triangle ABC that exists.
A= 37° a = 3.3 c= 15.3
Select the correct choice below and, if necessary, fill in the answer boxes within the choice.
O A. There are two possible solutions for the triangle.
The measurements for the solution with the longer side b are as follows.
B, =
C, =
The measurements for the solution with the shorter side b are as follows.
B2 =
C2 =°
b2 =
(Round to the nearest tenth as needed.)
B. There is only one possible solution for the triangle.
The measurements for the remaining angles B and C and side b are as follows.
B=
C=
b=
(Round to the nearest tenth as needed.)
OC. There are no possible solutions for the triangle.
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