Solve each equation. Check for extraneous solutions. 1. (x - 2)²/3 = 25 2 (4-2) ² - 15625 = X = -123 2. x3/2-10 - 54 x MINMIN 3-10=54 12월 26915:0 x-16 X= 127 3 Y - 46 96 Check: Check:

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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125
5-5
25
Solve each equation. Check for extraneous solutions.
1. (x - 2)²/3 = 25
-21² - 15625
X = -123
1
2. x3/2-10 - 54
x ² -10=54
72
264
x-16
X= 127
3
Y-
46
196
Check:
Check:
+
-13
C
JIM
Transcribed Image Text:125 5-5 25 Solve each equation. Check for extraneous solutions. 1. (x - 2)²/3 = 25 -21² - 15625 X = -123 1 2. x3/2-10 - 54 x ² -10=54 72 264 x-16 X= 127 3 Y- 46 196 Check: Check: + -13 C JIM
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