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Solve (D2 + 4) y = 5e" – 4x. - y = ce=2» + cze2" +2xe2" + 3 y = c1 sin 2x + c2 cos 2x + e® y = c1 + C2a + c3 cos e + C4 sin a + a - 3x² + æ sin a+ 2x cos a y = c1 e" + cze2 + 2 + 3a + + 2e - a e" – 3xe"

Solve (D2 + 4) y = 5e" – 4x. - y = ce=2» + cze2" +2xe2" + 3 y = c1 sin 2x + c2 cos 2x + e® y = c1 + C2a + c3 cos e + C4 sin a + a - 3x² + æ sin a+ 2x cos a y = c1 e" + cze2 + 2 + 3a + + 2e - a e" – 3xe"

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Solve (D2 + 4) y = 5e" – 4x. y = c1e=2# + c2 e2" + 2xe2* + 3 y = c1 sin 2x + c2 cos 2x + e# – x y = c1 + C2¤ + c3 cos x + c4 sin æ + æª – 3x² + x sin a + 2x cos a y = c1e# + c2e²a + x² + 3x + % + 2e3 – a² e® - 3xe
Transcribed Image Text:Solve (D2 + 4) y = 5e" – 4x. y = c1e=2# + c2 e2" + 2xe2* + 3 y = c1 sin 2x + c2 cos 2x + e# – x y = c1 + C2¤ + c3 cos x + c4 sin æ + æª – 3x² + x sin a + 2x cos a y = c1e# + c2e²a + x² + 3x + % + 2e3 – a² e® - 3xe
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