Solve (c) and (d) part : QUES) Consider a lattice with N sites and n green particles. Consider another lattice, adjacent to the first, with M sites and m red particles. Assume that the green and red particle cannot switch lattice. This is state A (a) What is the total number of configurations ΩA of the system in state A? (b) Now assume that all N + M sites are available to all green and red particles. The particles remain distinguishable by their color. This is state B. Now what is the total number of configurations ΩB of the system (c) Using Stirling’s approximation, what is the ratio ΩA/ΩB? (d) Which state, A or B, has the greatest entropy? calculate the entropy difference.
Solve (c) and (d) part : QUES) Consider a lattice with N sites and n green particles. Consider another lattice, adjacent to the first, with M sites and m red particles. Assume that the green and red particle cannot switch lattice. This is state A (a) What is the total number of configurations ΩA of the system in state A? (b) Now assume that all N + M sites are available to all green and red particles. The particles remain distinguishable by their color. This is state B. Now what is the total number of configurations ΩB of the system (c) Using Stirling’s approximation, what is the ratio ΩA/ΩB? (d) Which state, A or B, has the greatest entropy? calculate the entropy difference.
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Solve (c) and (d) part :
QUES) Consider a lattice with N sites and n green particles. Consider another lattice,
adjacent to the first, with M sites and m red particles. Assume that the green and
red particle cannot switch lattice. This is state A
(a) What is the total number of configurations ΩA of the system in state A?
(b) Now assume that all N + M sites are available to all green and red particles.
The particles remain distinguishable by their color. This is state B. Now what is
the total number of configurations ΩB of the system
(c) Using Stirling’s approximation, what is the ratio ΩA/ΩB?
(d) Which state, A or B, has the greatest entropy? calculate the entropy difference.
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