Solve by the substitution method. (If there is no solution, enter NO SOLUTION. Use the parameters x and y as necessary.) Зх — бу %3D —27 -x + 2y = 9 {х, у) %3D
Solve by the substitution method. (If there is no solution, enter NO SOLUTION. Use the parameters x and y as necessary.) Зх — бу %3D —27 -x + 2y = 9 {х, у) %3D
Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter9: Systems Of Linear Equations
Section9.2: The Substitution Method
Problem 1WE
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![Solve by the substitution method. (If there is no solution, enter NO SOLUTION. Use the parameters x and y as necessary.)
Зх — бу
= -27
-x + 2y
9.
(х, у) %3D](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fca700b25-5c4d-4524-8e45-53dcd11a3e9a%2F42b9e944-b8c9-4e56-81ba-9d36cd63ee7e%2F9wyplt9_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Solve by the substitution method. (If there is no solution, enter NO SOLUTION. Use the parameters x and y as necessary.)
Зх — бу
= -27
-x + 2y
9.
(х, у) %3D
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