Solve by the method of integrals with sines and cosines: f3e³x sin² (e³x) dx

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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ФЫ В А ПРО ВА ПРО Л ДЗАПРОЛДЖЫВАПР
ЯЧСМИТНЧСМИТЬБАСМИТЬБЮ ЯЧСми
DON'T USE AI | DON'T USE AI [DON'T USE AI | DON'T USE AI | DON'T USE AI
SOLVE STEP BY STEP IN DIGITAL
Solve by the method of integrals with sines and
cosines:
f3e3x sin²(e3x) dx
FORMAT
УКЕНГШУИЦУКЕНГШУКЕНГШЩЗКЕНГШ щ.
УКЕНГШУЙЦУКЕНГШУКЕНГШЩЗКЕНГШЩ:
IBA ПPO» B ФЫ В А П Р О ВАПРОЛДЗАПРОЛД
СМИТНЧСМИТЯЧСМИТНЧСМИТЬБНСМИТЕ
"
Transcribed Image Text:ФЫ В А ПРО ВА ПРО Л ДЗАПРОЛДЖЫВАПР ЯЧСМИТНЧСМИТЬБАСМИТЬБЮ ЯЧСми DON'T USE AI | DON'T USE AI [DON'T USE AI | DON'T USE AI | DON'T USE AI SOLVE STEP BY STEP IN DIGITAL Solve by the method of integrals with sines and cosines: f3e3x sin²(e3x) dx FORMAT УКЕНГШУИЦУКЕНГШУКЕНГШЩЗКЕНГШ щ. УКЕНГШУЙЦУКЕНГШУКЕНГШЩЗКЕНГШЩ: IBA ПPO» B ФЫ В А П Р О ВАПРОЛДЗАПРОЛД СМИТНЧСМИТЯЧСМИТНЧСМИТЬБНСМИТЕ "
Expert Solution
Step 1: Define the substitution

Given integral is integral 3 e to the power of 3 x end exponent sin squared left parenthesis e to the power of 3 x end exponent right parenthesis d x

Let, e to the power of 3 x end exponent equals u

Then, 3 e to the power of 3 x end exponent d x equals d u [ since, fraction numerator d over denominator d x end fraction left parenthesis e to the power of a x end exponent right parenthesis equals a e to the power of a x end exponent]

substitute the above values in the given integration we get,

integral 3 e to the power of 3 x end exponent sin squared left parenthesis e to the power of 3 x end exponent right parenthesis d x equals integral sin squared left parenthesis e to the power of 3 x end exponent right parenthesis left curly bracket 3 e to the power of 3 x end exponent d x right curly bracket

                           equals integral sin squared u space d u

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