Solve by the indirect Croos method and calculate the second column of the lateral stiffness matrix (Ri2, 02 = 1) of the cantilever wall, which can be achieved by applying the Cross method (only with rotational degrees of freedom). KB Where: kB=22500 Km=18352.94 fp=0.27 uij=-36279 (3) → R32 2.5 m km d2 = 1 → R22 (2) (3) d2 = 1 R12 R32 R22 ล km (1) Km Ks 2.5 m R12 2.5 m KB = Ks Foundation rotation stiffness Km=3E1/[h3(1+g/2)]= rig, to turn cantilever wall fp (1-g)/(2+g) plate transport factor g=6 Elpf/G Ap h2 uij (cantilever wall) = - 6 Elpd/(h2 (1+2 g)) Calculate Mij times Cross Then. calculate Ri2 by equilibrium Calculation of the Second Column of the Lateral Stiffness Matrix {Ri2} in an Axis Vertical 3 Levels The rest of the columns of the lateral stiffness matrix ({ Ri1} and {Ri3 }), corresponding to the system shown in the previous Fig, are obtained by releasing levels 1 and 3, independently, following the indicated process, which leads for each vertical axis to: | R11 R12 R13 | [R] R21 R22 R23 symmetrical about the diagonal | R31 R32 R33 |