Solve and check the equation. X X - 15 6. ..... What is the solution? Select the correct choice below and, if necessary, fill in the answer box to complete your choice. O A. The solution set is { O B. The solution set is {x |x is a real number}). O C. The solution set is Ø.

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A:

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A:

Q: Solve for x. 11**-16-& 8x Round your answer to the nearest thous Do not round any intermediate compa

A: 11x+6=16-8x

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A: Here,

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A: The given figure is  We have to find the value of m and n. The measure of opposite angles of a…

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A: Given quadretic inequality is 12.  2x2+12x≥4x-8   Note: As per Bertleby Guideline I have to solve…

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Q: Solve for x. 196 X=

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Q: 9. Solve for x. Round to the nearest tenth if necessary. X-4=-2x+9

A: solve x

Q: Decide whether the given equation is an identity, a conditonal equation, or a contradiction.…

A: Decide whether the given equation is an identity, a conditonal equation, or a contradiction.…

Q: 2x + 2 x + 3 21 12 12 a+3 21 2x+2 2x+2 r+3 エ+3 %3D 2x+2 21 a+3 12 2x+2 O O O O

A: topic - ratios

Q: 3 3 = 0, then x = ? Зх — 8 13. If 3 Зх - 8 3 3 3 3x – 8|

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Q: Solve for x, where x is a real number. 9 4x = 8 27

A: The answer is x=1/6 (No option is correct)

Q: Solve. −23< 4x −3 ≤ 1 The answer in interval notation is??

A: We have given that the interval -23&lt; 4x −3 ≤ 1 We want to find the interval of x in notation.

Q: Simplify each expression. a. +(-4) b. -9- c.

A: Given (a) 29+-12(b) -67-35we have to simplify these expression

Q: +X = -8 O29 14 2. 1. 790

A: 72199401-8+X =03-62819-7-5X=?

Q: M 5х — 6 'N 2х + 9

A: straight line angle is 180

Q: Solve for the value(s) of x: /=15 – 2x = v2x + 21 (show steps on paper and upload it to last…

A:

Q: Solve the equation |x – 12|– 5 = 17 A. X = 10 and – 34 B. x = -10 and – 34 C. x = 10 and 34 D. x…

A: Given equation is x−12−5=17. We have to solve the given equation. Add both sides 5 and further…

Q: Solve for X. X = -5 -57 61 4 X + 2 1 4 21] = X.

A: To solve for X.-5-5-24X+-2412=2-99-8X

Q: Solve. |x-2+6=9 State the two equations that arise after writing the equation in the form |X|= a and…

A: To solve an absolute value function, such as |x|=p, replace it with the two equations x=−p and x=p.…