Solve 9tan(20) – 3/3 = 0 exactly on 0 < 0 < 2n. л 7л 13л 19л 0 = 12' 12' 12' 12 5л 11л 17я 23л 12' 12' 12 12 12' 12 л 2л 7л 5л 6' 3' 6'3 = A 6' 6 II
Solve 9tan(20) – 3/3 = 0 exactly on 0 < 0 < 2n. л 7л 13л 19л 0 = 12' 12' 12' 12 5л 11л 17я 23л 12' 12' 12 12 12' 12 л 2л 7л 5л 6' 3' 6'3 = A 6' 6 II
Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE:
1. Give the measures of the complement and the supplement of an angle measuring 35°.
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![Solve 9tan(20) – 3V3 = 0 exactly on 0 < 0 < 2n.
л 7л 13л 19л
0 =
12' 12' 12' 12
5л 11л 17л 23л
12' 12' 12 12
12' 12
л 2л 7л 5л
6 3'6'3
6' 6](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Faaf93c2d-7d7d-4bd0-8e29-b8c7e2d7c96c%2F998ea525-8031-4d39-8709-6adaaa90ddb4%2Fnwwzpgrp_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Solve 9tan(20) – 3V3 = 0 exactly on 0 < 0 < 2n.
л 7л 13л 19л
0 =
12' 12' 12' 12
5л 11л 17л 23л
12' 12' 12 12
12' 12
л 2л 7л 5л
6 3'6'3
6' 6
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