Solve: -3z? – 6z – 2 = 5z2 – 10z – 10 Enter your answer in the form a + bi.

Q: Solve by substitution  x + 4y =17 8x- 7y= 58

A: Answer

Q: Solve: (2x – 3)3 + 3 = 0.

A:

Q: 6b. x =8x- 15

A: 6b Given Data: Equation: x2=8x-15 Rewrite the given equation. x2=8x-15x2-8x+15=0

Q: b. Solve: 1 +Vx + 4 =V3x +1

A: We will solve the equation as following.

Q: Solve for x if: -3x + 3 = -6(x - 7) (Round your answer to two decimal places)

A: Given that, -3x+3=-6x-7

Q: Solve: Vx – 3 + 6 = 5.

A: The given equation is x-3+6=5

Q: Зх + 2 9 3— 2х 4 4 6.

A:

Q: Solve: z2 + 4 = 0.

A:

Q: olve z2 -4z+

A: we have to solve the,  z2 -4z+29=0 compare with,  a=1 b=-4 and c=29

Q: Solve for w. 38= -6w - 7w - 27

A:

Q: solve : 3r + 2 - 5(r + 1) = 6r + 4

A: Solution:- Given a equation, 3r+2-5r+1=6r+4 We need to solve the given equation.

Q: Solve: x? + + 27 = 12x.

A: Given: x2+27=12x

Q: Solve the following y = -3x + 3; (2, 6) %3D

A:

Q: Solve 5x – 23x² + 29x – 15 = 0. - + १+, 4 급+,29

A:

Q: 6x9y+ z = −12 2x - 3y z = −4 - -4 -8x + 12y = 16

A: On solving this we will get

Q: Solve: y² + 2xy = 1 + x² + y²

A:

Q: Solve: (3x – 1)3 + 4 = 0.

A: We solve the equation as,

Q: Solve by substitution  4x+7y=-59

A: Given equations: 4x+7y=-59.......(1) 3x+y=-23..........(2) From the equation 1, 4x=-59-7y…

Q: Solve for x: 6+3 - 6 = 215. 01 06 O-1 O o

A:

Q: 146-d solve for d

A:

Q: Solve:  3x + 2y = z + 2y = 1 − 2x3z = − 2y

A: We substitute y=1-2x in first equation.

Q: Solve the following quadratic equation: 2x2 + a - 6 = 0 0 {-;,2} O {},2} o {;,-2} o{-클,-2}

A: To solve the below quadratic equation. 2x2+x−6=0

Q: Solve: x2 – 14x = -45

A: The equation is given as x2-14x=-45

Q: Solve −2x2 − 16x − 44 = 0

A:

Q: solve for the value of "a" in the equation a- 17a + 16 = 0.

A: