Solve: 3 1= - z+ 3 3z z+3 O 2

Q: b. Solve: 1 +Vx + 4 =V3x +1

A: We will solve the equation as following.

Q: Solve: -2x - 4 = x + 5.

A: We subtract x from both sides

Q: Зх + 2 9 3— 2х 4 4 6.

A:

Q: 2. X-7 4x+1 3.

A: NOTE: Refresh your page if you can't see any equations. . as we know denominator cannot be zero…

Q: Solve: z2 + 4 = 0.

A:

Q: olve z2 -4z+

A: we have to solve the,  z2 -4z+29=0 compare with,  a=1 b=-4 and c=29

Q: Solve:  7a3(2a4)3

A:

Q: Solve (-2 - 3)square + 4 3cube/2

A: First combine -2-3that is -5.And 3 cube= 27

Q: solve : 3r + 2 - 5(r + 1) = 6r + 4

A: Solution:- Given a equation, 3r+2-5r+1=6r+4 We need to solve the given equation.

Q: Solve: 2 0 -1 0 2 -6 1 -2 -3 -2 0 1 -5

A:

Q: Solve: a² + 12a = -27

A:

Q: Solve: 3x – 5 -3.

A: Given: 3x-5≤13 or 5x+2>-3 To Find: To solve the given inequalities.

Q: Solve : 2x + 8 = x - 4

A: Given:2x+8=x-4

Q: Solve:  m + 6n + 3p = 83m + 4n = − 35m + 7n = 1

A: We are given, m + 6n + 3p = 8   ----(1)       3m + 4n = − 3 ------(2)       5m + 7n = 1  ------(3)…

Q: solve: 3x-5y=-3           2x-3y=-1

A: To solve the system of linear equations

Q: Solve: 2t² + 18t - 1 = 6t - 3t²

A:

Q: Solve by substitution  4x+7y=-59

A: Given equations: 4x+7y=-59.......(1) 3x+y=-23..........(2) From the equation 1, 4x=-59-7y…

Q: Solve:  3x + 2y = z + 2y = 1 − 2x3z = − 2y

A: We substitute y=1-2x in first equation.

Q: Solve: 2t² + 18t - 1 = 6t - 3t²

A:

Q: Solve: 18x2 + 12x = -23

A: Given Quadratic Equation 18x2 + 12x = -23