Solution- (h) رف) (g) X-2 So accordind to As So I'm f(x) = ? we lim £(2) 2-12 22=1 сан are O -2- No of discontinuity -4- I approaches to function's value is approaches to see the given graph P 2 x=1 ਸ 2 O ។ from graph no. of discontinuity there S [at x==2, x=-1₁ 2²=0, x=1, X=2] For ese essential discontinuity left limit or right limit or both must approach to the en infinity, Then the discontinuity is essential. P.N.I. 1x graph directly 0.

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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Solutioni-
(h)
رف)
(g)
cill
I'm f(21) = ?
X-2
we
lim £(2) = 0
भन
-5-4
So according to the given graph
As
I approaches to
function's value is approaches to
сам
жет у
No of discontinuity
are
2
کی
2
221
2
$
see from graph directly
no. of discontinuity
there
[ at 2=-2, x=-1₁ 41=0, x=1, x=2]
P.N.L.
1x
0.
For
ese essential discontinuity
left limit or right limit or both
must approach to the
to the en énfinity,
Then
the discontinuity is essential.
Transcribed Image Text:Solutioni- (h) رف) (g) cill I'm f(21) = ? X-2 we lim £(2) = 0 भन -5-4 So according to the given graph As I approaches to function's value is approaches to сам жет у No of discontinuity are 2 کی 2 221 2 $ see from graph directly no. of discontinuity there [ at 2=-2, x=-1₁ 41=0, x=1, x=2] P.N.L. 1x 0. For ese essential discontinuity left limit or right limit or both must approach to the to the en énfinity, Then the discontinuity is essential.
Clearly
(G)
at x=-1
approaches to infinity.
at x=-
So
at x=1
So
So
by
In
IL
left and right both I'mits
to infinity.
at x=1
Removable!
there is essential
discontinuity,
the left limit approaches
at x=+ and 21=1
discontinuity.
are
there is
discontinuity.
Discontinuity
By these kind of
redifine the
given for
discontinuity at
have essential
fx",
essential
X=0
we redefine the for
at x=0=f121=0
and
21=2 = f(2)=4
P.N.2
сам
removable discontinity
remove
1 x = 1
then there will be no discontinuity at
& Dr=2.
do
west
Transcribed Image Text:Clearly (G) at x=-1 approaches to infinity. at x=- So at x=1 So So by In IL left and right both I'mits to infinity. at x=1 Removable! there is essential discontinuity, the left limit approaches at x=+ and 21=1 discontinuity. are there is discontinuity. Discontinuity By these kind of redifine the given for discontinuity at have essential fx", essential X=0 we redefine the for at x=0=f121=0 and 21=2 = f(2)=4 P.N.2 сам removable discontinity remove 1 x = 1 then there will be no discontinuity at & Dr=2. do west
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