Given H(jw) -(4+jw) 6+5jw-w² an rewrite as:- (jw+4) -+₁) 6+ (jw)² + 5jw (jw+ 4) (jw+3) (jw+2) (jw+3) + २ (jus+2) by partial fre все get, F How did he get the value inside the circle ) + 4x(i) (jw)

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Solution:-
Given H(jw) -(4+jw)
6+5jw-w²
It Can rewrite as:- (jw+4)
(: j² = + D)
6+ (jw)² + 5jw
-(ja+ 4)
(+3) (jw+2) (jw+3)
(Jષ્મ 2)
How did he get the
value inside the circle
(by partial fraction)
& we get, A=-1 & B=2
(jw) + 4x (jw)
Transcribed Image Text:Solution:- Given H(jw) -(4+jw) 6+5jw-w² It Can rewrite as:- (jw+4) (: j² = + D) 6+ (jw)² + 5jw -(ja+ 4) (+3) (jw+2) (jw+3) (Jષ્મ 2) How did he get the value inside the circle (by partial fraction) & we get, A=-1 & B=2 (jw) + 4x (jw)
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