Solution :E 200(10°)E 1110° )The width of steel must be increased to an equivalent width for wood:Page 1=18.182W.mm1I =width (A|(10*) m²Failure of wood:Mc(6.I0.5MA20(10° ) =M =ANmIFailure of steel:nMcst /maxI(18.182)0.5MA).130(10° ) –NmM =AnsI Question 2 :The composite beam consists of a wood core and two plates of steel. If the allowable bend ngstress for the wood is (oaiow )y = 20MPaand for the s(o aienl =130MPAzilowdetermine the maximum moment that can be applied to the beam.E, =11GPA , E= 200GPATake:A =125 mmA mmB =75mmM20 mm-B mm20 mmSolution :E 200(10"E 1110°The width of steel must be increased to an equivalent width for wood:Page 118.182W.mm

Answered: Image /qna-images/answer/b5d5102c-245a-4fc4-8cad-8e2c10bb2c5a.jpg

Solution : Е, 200(10°) E 11(10° The width of steel must be increased to an equivalent width for wood: Page 1 -18.182 mm 1 width (A |(10³) m² Failure of wood: Mc 0.5MA 20(10°) = I M = kNm Failure of steet I 130(10) – (18.182 (0.5MA). М- Ans

Solution : Е, 200(10°) E 11(10° The width of steel must be increased to an equivalent width for wood: Page 1 -18.182 mm 1 width (A |(10³) m² Failure of wood: Mc 0.5MA 20(10°) = I M = kNm Failure of steet I 130(10) – (18.182 (0.5MA). М- Ans

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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