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Solution Also kalhere, are two continously differentiable rreal valued function and c is given Given that f(x,y) and g(x,y) constant.. that v is unit vector in R². Now, Prove that, v ( + ) = 2 əx We have, f -(+) g 3. g Vf-fVg (del) is differential opratore. V ˇ ( ) = ³ ¦ (‡) +¹ ÷ (‡) + (†) x dx lale know that by the partial fraction. differentiation such that g af ex ag fax g² similarly, and, 2 2 dz -(+) = ▼( - ) - 83 - 832 g² Therefore, Hence, of f 129 + k g g² H Iz g² Mow, Substitute these value in general equation we get, - 29 faz g ag by got - for =9f-fv g g² [-] бу at f sy 7 · ( ) = + ( [# - 3 + + + ² 2 ) = g² (132 +38-+*32)] ay Proved

Solution Also kalhere, are two continously differentiable rreal valued function and c is given Given that f(x,y) and g(x,y) constant.. that v is unit vector in R². Now, Prove that, v ( + ) = 2 əx We have, f -(+) g 3. g Vf-fVg (del) is differential opratore. V ˇ ( ) = ³ ¦ (‡) +¹ ÷ (‡) + (†) x dx lale know that by the partial fraction. differentiation such that g af ex ag fax g² similarly, and, 2 2 dz -(+) = ▼( - ) - 83 - 832 g² Therefore, Hence, of f 129 + k g g² H Iz g² Mow, Substitute these value in general equation we get, - 29 faz g ag by got - for =9f-fv g g² [-] бу at f sy 7 · ( ) = + ( [# - 3 + + + ² 2 ) = g² (132 +38-+*32)] ay Proved

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Solution Also where, Given that f(x,y) and g(x,y) are two continously differentiable rreal valued function and c is given Now, Prove that, v ( + ) = constant. that v is unit vector in R². 2 əx We have, f (1) . V ˇ ( ) = ³ & (‡) +¹ ÷ (‡) + (†) x dx lale know that by the partial fraction differentiation such that = g Vf-fVg (del) is differential opratore. g af ex ag fax g² similarly, and, 2 2 dz -(+) = Therefore, Hence, ▼(-7) - [832 - 432 + ag of fay 129 Mow, general equation we get, g² g² + k H g Iz g² Substitute these value in - 29 faz g got - for 2f =9f-fv g g² sy --f g² g V · ( + ) = + ( [# - 3 + + + ²) = бу (132 +38-+*32)] ay Proved
Transcribed Image Text:Solution Also where, Given that f(x,y) and g(x,y) are two continously differentiable rreal valued function and c is given Now, Prove that, v ( + ) = constant. that v is unit vector in R². 2 əx We have, f (1) . V ˇ ( ) = ³ & (‡) +¹ ÷ (‡) + (†) x dx lale know that by the partial fraction differentiation such that = g Vf-fVg (del) is differential opratore. g af ex ag fax g² similarly, and, 2 2 dz -(+) = Therefore, Hence, ▼(-7) - [832 - 432 + ag of fay 129 Mow, general equation we get, g² g² + k H g Iz g² Substitute these value in - 29 faz g got - for 2f =9f-fv g g² sy --f g² g V · ( + ) = + ( [# - 3 + + + ²) = бу (132 +38-+*32)] ay Proved
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