SOLUTION 1: Sam's Solution SOLUTION 2: Sheena’s Solution SOLUTION 3: Sari's Solution Sam's Solution Sheena's Solution Sari's Solution 21 4 5 -16 -3 21 5 -16 4 -3 -2| 4 5 -16 -3 8 26 20 10 -12 -16 -8 20 4 13 10 17 -6 -8 -19 -3 -10 17 Therefore, the quotient is 17 4x2 + 13x + 10 + Therefore, the quotient is Therefore, the quotient is 17 4x2 — Зх — 10+ 19 5x2 — 6х — 8 х — 2 x-2 X – 2

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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LEARNING COMPETENCY: Analyze problems involving polynomial equations

DIRECTIONS: Below are three solutions to the problem below. Analyze the given solutions and select the best among the three. Write your answer in the given table.

1. Sam and Sheena were studying for the upcoming quarter exam. They encountered a problem about division of polynomials, and they tried to solve it by individually computing for the quotient and remainder of (5?2 − 16? + 4?3 − 3) divided by (x – 2).

 *see image of solutions*

DIRECTIONS: After analyzing the three solutions, decide which of the three is the best. Discuss your choice and support your answer with the parts of the solutions pointing out the correctness of the chosen solution or the error/s made on the others.

ANSWER:

Solution no. ______ of _________________ is the best solution because...

 

SOLUTION 1: Sam's Solution SOLUTION 2: Sheena’s Solution SOLUTION 3: Sari's Solution
Sam's Solution
Sheena's Solution
Sari's Solution
21 4 5
-16
-3
21 5
-16
4
-3
-21
4 5
-16
-3
8
26
20
10
-12
-16
-8
20
4
13
10
17
-6
-8
-19
4
-3
-10
17
Therefore, the quotient is
Therefore, the quotient is
17
4x2 + 13x + 10 +
19
5x2 – 6x – 8 –
x-2
Therefore, the quotient is
17
4x2 — Зх — 10 +
-
х — 2
-
х — 2
Transcribed Image Text:SOLUTION 1: Sam's Solution SOLUTION 2: Sheena’s Solution SOLUTION 3: Sari's Solution Sam's Solution Sheena's Solution Sari's Solution 21 4 5 -16 -3 21 5 -16 4 -3 -21 4 5 -16 -3 8 26 20 10 -12 -16 -8 20 4 13 10 17 -6 -8 -19 4 -3 -10 17 Therefore, the quotient is Therefore, the quotient is 17 4x2 + 13x + 10 + 19 5x2 – 6x – 8 – x-2 Therefore, the quotient is 17 4x2 — Зх — 10 + - х — 2 - х — 2
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