solle не ۱/۱ 2 z² + 1 ²+1 dz 3 3 cus x sin³ x dx で T=T [く] M

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A: Thus, the final result is: dxd​∫2sinx​ln(t)dt=ln(sinx)⋅cosx

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Q: العنوان solle o dx (x-2)√√x=4x+3 ۱/۱ S (1+ cos x) dx 2 Sin X T =T ☑ M

A: solution of the given question is like as:

Q: how to solve this question

A: Step 1: Step 2: Step 3: Step 4:

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A: The integral we are trying to solve is ∫cos(ln(x))dx.

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A: Solution of the given question is like as

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Q: оне dx 2 X√1+Lu² (x²) Secx sin 3x d x ۱/۱ ✓ で [H T =T TH ☑ M

A: Step 1:Step 2:

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A: Step 1: Step 2: Step 3: Step 4:

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