Sol. Since AU = 0, then the heat on segment ab is QH = TH In | The heat on segment cd is QC = - TC In | By inspection, we can say that and TH Y-1. Thus, Vb/ then IQC/QH| | Which solves the efficiency of the Carnot engine.

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
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Calculate the efficiency of the Carnot Engine for ideal gas. Consider the figure below for a complete cycle of Carnot engine, where the cycle goes from ad->ab->bc->cd

(17 blanks) Calculate the efficiency of the Carnot Engine for ideal gas. Consider the figure below for a complete cycle of Carnot engine, where the cycle goes from ad->ab->bc->cd
Carnot cycle
Он
TH
Tc
V
O2016 Pearson Education, Inc.
processes; and the volumes involved are Va, Vb, Vc, Vd, and the two temperatures TC and
processes and segment ab & cd are the
Where segments ad & bc are the
Transcribed Image Text:(17 blanks) Calculate the efficiency of the Carnot Engine for ideal gas. Consider the figure below for a complete cycle of Carnot engine, where the cycle goes from ad->ab->bc->cd Carnot cycle Он TH Tc V O2016 Pearson Education, Inc. processes; and the volumes involved are Va, Vb, Vc, Vd, and the two temperatures TC and processes and segment ab & cd are the Where segments ad & bc are the
Sol.
Since AU = 0, then the heat on segment ab is
QH =
TH In |
The heat on segment cd is
QC = -
TC In |
By inspection, we can say that
THV-1
Vr-1
b
and
TH
y-1.
VY-1
Thus,
Vb/
then
|QC/QH| = |
Which solves the efficiency of the Carnot engine.
Transcribed Image Text:Sol. Since AU = 0, then the heat on segment ab is QH = TH In | The heat on segment cd is QC = - TC In | By inspection, we can say that THV-1 Vr-1 b and TH y-1. VY-1 Thus, Vb/ then |QC/QH| = | Which solves the efficiency of the Carnot engine.
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