SO₂(g) + Cl₂(g) = SO₂Cl₂(g) AH = -264 kJ K = 34.5 When the reaction is altered, as below, what is the value of the enthalpy, AH°? 3SO₂(g) + 3Cl₂ (g) = 3SO₂Cl₂(g) ΔΗ = [ ? ] kJ

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**Thermodynamics of Chemical Reactions**

**Given Reaction:**

\[ \text{SO}_2(g) + \text{Cl}_2(g) \rightleftharpoons \text{SO}_2\text{Cl}_2(g) \]

- Enthalpy change (\(\Delta H^\circ\)): \(-264 \, \text{kJ}\)
- Equilibrium constant (\(K\)): 34.5

**Question:**

When the reaction is altered, as below, what is the value of the enthalpy (\(\Delta H^\circ\))?

**Altered Reaction:**

\[ 3\text{SO}_2(g) + 3\text{Cl}_2(g) \rightleftharpoons 3\text{SO}_2\text{Cl}_2(g) \]

\[ \Delta H = \, [?] \, \text{kJ} \]

**Instruction:**

Include either a \(+\) or \(-\) sign AND the magnitude in your answer.

**Input Box:**

\[ \text{Enthalpy (kJ)} \ \ \ \ \ \ \_\_\_\_\_\_ \ [\text{Enter}] \]

---

**Explanation:**
In this problem, we are given a chemical reaction with its associated enthalpy change and equilibrium constant. The enthalpy change (\(\Delta H^\circ\)) for the original reaction of one mole of \(\text{SO}_2\) and one mole of \(\text{Cl}_2\) forming one mole of \(\text{SO}_2\text{Cl}_2\) is \(-264 \, \text{kJ}\).

The problem asks us to determine the enthalpy change (\(\Delta H^\circ\)) for a similar but scaled reaction where the amounts of reactants and products are tripled. Since enthalpy is an extensive property, scaling the amounts of substances in a reaction multiplies the enthalpy change by the same factor. Therefore, the enthalpy change for the altered reaction will be \(3 \times (-264 \, \text{kJ}) = -792 \, \text{kJ}\).

You need to enter the correct value of \(\Delta H\) for the altered reaction in the provided input box. The value should reflect both the sign and magnitude. For example, you would input: \(-
Transcribed Image Text:**Thermodynamics of Chemical Reactions** **Given Reaction:** \[ \text{SO}_2(g) + \text{Cl}_2(g) \rightleftharpoons \text{SO}_2\text{Cl}_2(g) \] - Enthalpy change (\(\Delta H^\circ\)): \(-264 \, \text{kJ}\) - Equilibrium constant (\(K\)): 34.5 **Question:** When the reaction is altered, as below, what is the value of the enthalpy (\(\Delta H^\circ\))? **Altered Reaction:** \[ 3\text{SO}_2(g) + 3\text{Cl}_2(g) \rightleftharpoons 3\text{SO}_2\text{Cl}_2(g) \] \[ \Delta H = \, [?] \, \text{kJ} \] **Instruction:** Include either a \(+\) or \(-\) sign AND the magnitude in your answer. **Input Box:** \[ \text{Enthalpy (kJ)} \ \ \ \ \ \ \_\_\_\_\_\_ \ [\text{Enter}] \] --- **Explanation:** In this problem, we are given a chemical reaction with its associated enthalpy change and equilibrium constant. The enthalpy change (\(\Delta H^\circ\)) for the original reaction of one mole of \(\text{SO}_2\) and one mole of \(\text{Cl}_2\) forming one mole of \(\text{SO}_2\text{Cl}_2\) is \(-264 \, \text{kJ}\). The problem asks us to determine the enthalpy change (\(\Delta H^\circ\)) for a similar but scaled reaction where the amounts of reactants and products are tripled. Since enthalpy is an extensive property, scaling the amounts of substances in a reaction multiplies the enthalpy change by the same factor. Therefore, the enthalpy change for the altered reaction will be \(3 \times (-264 \, \text{kJ}) = -792 \, \text{kJ}\). You need to enter the correct value of \(\Delta H\) for the altered reaction in the provided input box. The value should reflect both the sign and magnitude. For example, you would input: \(-
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