Soft Drink Consumption A researcher claims that the yearly consumption of soft drinks per person is 52 gallons. In a sample of 58 randomly selected people, the mean of the yearly consumption was 53.1 gallons. The standard deviation of the population is 3.5   gallons. On the basis of the P-value, is the researcher's claim valid at   α=0.02? Use a graphing calculator.  Find the P-value. Round the answer to at least four decimal places.  P-value=

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A: Given that  Mean = 0 , Standard deviation = 1

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A: μ = 100σ = 15 X = 115

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A: Solution

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Q: The estimated standard deviation is°F. (Round to two decimal places as needed.) Compare the result…

A:

Q: Find the indicated IQ score. The graph to the right depicts IQ scores of adults, and those scores…

A: Let X be IQ score  from normal distribution with mean (μ) = 100 and standard deviation (σ) = 15

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A: We have to find correct option.

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A: Given,mean(μ)=100standard deviation(σ)=15and z-score=0.7

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A: To solve this problem, we need to find the 17th percentile (P17) of a normally distributed dataset…

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A: We have given that The IQ scores are normally distributed with  Mean(µ) = 100 and Standard…

Q: Find the indicated IQ score. The graph to the right depicts IQ scores of​ adults, and those scores…

A: The Z-score of a random variable X is defined as follows: Z = (X – µ)/σ. Here, µ and σ are the mean…

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A:

Q: 0.2743 d.)

A: For a random variable, X~N(μ,σ2), the z-score is, Z=X-μσ    .... (1)where, μ=population…

Q: Find the indicated IQ score. The graph to the right depicts IQ scores of adults, and those scores…

A: Given information Mean = 100 Standard deviation = 15 P(X > x) = 0.65 P(X < x) = 1 – 0.65 =…

Q: the average grade is 84 with a standard deviation of 4. What is each grade for -1 2 0 1.5 -1.25

A: Given Mean μ=84Standard deviation σ=4 The formula for Z score isZ=X-μσX=Z×σ+μ

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Q: The indicated IQ score, x, is (R

A: here mean = 100 standard deviation  = 15  X = IQ score

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A:

Q: .... The indicated IQ score, x, is (Round to one decimal place as needed.)

A:

Q: The lengths of pregnancies in a small rural village are normally distributed with a mean of 260 days…

A: From the provided information, Mean (µ) = 260 days Standard deviation (σ) = 16 days X~N (260, 16)

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A: Standard deviation(s)=2.3 miles

Q: Find the indicated IQ score. The graph to the right depicts IQ scores of adults, and those scores…

A:

Q: Find the indicated IQ score. The graph to the right depicts IQ scores of adults, and those scores…

A: Given: Mean μ = 100 Standard deviation σ = 15 Formula Used: Z = X-μσX = μ+Zσ

Q: Find the indicated IQ score. The graph to the right depicts IQ scores of​ adults, and those scores…

A: Given info: IQ scores of​ adults are normally distributed with a mean of 100 and a standard…

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A: GivenMean(μ)=0standard deviation(σ)=1

Q:

A: Given that IQ scores of adults is normally distributed with mean 100 and standard deviation 15. The…

Q: Find the indicated IQ score. The graph to the right depicts IQ scores of​ adults, and those scores…

A: It is given thatMean, μ = 100Standard deviation, σ = 15Z-Score, Z = ( X - μ )/σwhere, Z be the…