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Sodium hydroxide reacts with carbon dioxide as follows: 2NaOH(s)+CO2(g)→Na2CO3(s)+H2O(l)   How many moles of Na2CO3 can be produced?

Sodium hydroxide reacts with carbon dioxide as follows: 2NaOH(s)+CO2(g)→Na2CO3(s)+H2O(l)   How many moles of Na2CO3 can be produced?

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Sodium hydroxide reacts with carbon dioxide as follows:

2NaOH(s)+CO2(g)→Na2CO3(s)+H2O(l)

 

How many moles of Na2CO3 can be produced?

I Review I Constants I Periodic Table Sodium hydroxide reacts with carbon dioxide as follows: Submit Previous Answers 2NaOH(s) + CO2(g) → Na2 CO3 (s) + H20(1) Correct The limiting reactant is the one that is completely consumed during the reaction. According to the reaction stoichiometry, two moles of NaOH are consumed per one mole of CO2 in a complete reaction. The amount of NaOH needed for a complete consumption of 1.20 mol CO2 is 2 mol NaOH mol NaOH needed to react 1.20 mol CO, x 1 mol CO, 2.40 mol NaOH Since only 2.30 mol NaOH are available, NaOH will run out before all CO2 reacts. Therefore, NaOH is the limiting reactant. Part B How many moles of Na2 CO3 can be produced? Express your answer in moles to two decimal places. Α φ. ? n = |1.31 mol Submit Previous Answers Request Answer X Incorrect; Try Again; 3 attempts remaining
Transcribed Image Text:I Review I Constants I Periodic Table Sodium hydroxide reacts with carbon dioxide as follows: Submit Previous Answers 2NaOH(s) + CO2(g) → Na2 CO3 (s) + H20(1) Correct The limiting reactant is the one that is completely consumed during the reaction. According to the reaction stoichiometry, two moles of NaOH are consumed per one mole of CO2 in a complete reaction. The amount of NaOH needed for a complete consumption of 1.20 mol CO2 is 2 mol NaOH mol NaOH needed to react 1.20 mol CO, x 1 mol CO, 2.40 mol NaOH Since only 2.30 mol NaOH are available, NaOH will run out before all CO2 reacts. Therefore, NaOH is the limiting reactant. Part B How many moles of Na2 CO3 can be produced? Express your answer in moles to two decimal places. Α φ. ? n = |1.31 mol Submit Previous Answers Request Answer X Incorrect; Try Again; 3 attempts remaining
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