A student was asked to identify a sample of unknown hydrate. Student was provided with the following experimental data. 3.51 g sample of the hydrate when heated loses water completely and the mass of the residue was found to be 2.22 g. Student was provided with two reference compounds from which student needs to identify the unknown: Cu(NO3)2.3H20 and Cu(NO3)2.6H20. Answer the followings. a. Calculate percent water of hydration in the sample. (show your calculations) 3.51g 2.22g 1.29 [1.29g/3.51g] x 100 =36.75% 36.8 b. Identify the formula of the hydrate.
A student was asked to identify a sample of unknown hydrate. Student was provided with the following experimental data. 3.51 g sample of the hydrate when heated loses water completely and the mass of the residue was found to be 2.22 g. Student was provided with two reference compounds from which student needs to identify the unknown: Cu(NO3)2.3H20 and Cu(NO3)2.6H20. Answer the followings. a. Calculate percent water of hydration in the sample. (show your calculations) 3.51g 2.22g 1.29 [1.29g/3.51g] x 100 =36.75% 36.8 b. Identify the formula of the hydrate.
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Answer B and c
![## Experiment: Identifying an Unknown Hydrate
**Objective:** Determine the identity of an unknown hydrate using experimental data.
### Experimental Data:
- A 3.51 g sample of the hydrate loses water completely when heated.
- The mass of the residue after heating is 2.22 g.
### Task:
The student is provided with two reference compounds to help identify the unknown hydrate:
- Cu(NO₃)₂ ∙ 3H₂O
- Cu(NO₃)₂ ∙ 6H₂O
### Questions:
**a. Calculate the percent water of hydration in the sample.**
**Show your calculations:**
1. Calculate the mass of the water lost:
3.51 g (initial mass) - 2.22 g (residue mass) = 1.29 g
2. Determine the percent by mass of water:
\[
\text{Percent water} = \left(\frac{1.29 \, \text{g}}{3.51 \, \text{g}}\right) \times 100 = 36.75\%
\]
> Calculation result: **36.8%**
**b. Identify the formula of the hydrate.**
*Using the calculated percentage, compare with the reference compounds to determine the most likely hydrate formula.*
---
### Explanation:
In this experiment, the student calculates the percentage of water in a hydrate to determine its identity. By comparing the percentage with known hydrates, they can identify the chemical formula of the unknown compound. The percentage calculation involves comparing the mass of water lost to the original sample mass. This approach helps in understanding the composition of hydrate compounds.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F72e4817c-fc9d-4e3f-a33a-5ae87bf061ce%2F8d694d6f-b816-426d-bb71-b135a931ed24%2F1442toh_processed.jpeg&w=3840&q=75)
Transcribed Image Text:## Experiment: Identifying an Unknown Hydrate
**Objective:** Determine the identity of an unknown hydrate using experimental data.
### Experimental Data:
- A 3.51 g sample of the hydrate loses water completely when heated.
- The mass of the residue after heating is 2.22 g.
### Task:
The student is provided with two reference compounds to help identify the unknown hydrate:
- Cu(NO₃)₂ ∙ 3H₂O
- Cu(NO₃)₂ ∙ 6H₂O
### Questions:
**a. Calculate the percent water of hydration in the sample.**
**Show your calculations:**
1. Calculate the mass of the water lost:
3.51 g (initial mass) - 2.22 g (residue mass) = 1.29 g
2. Determine the percent by mass of water:
\[
\text{Percent water} = \left(\frac{1.29 \, \text{g}}{3.51 \, \text{g}}\right) \times 100 = 36.75\%
\]
> Calculation result: **36.8%**
**b. Identify the formula of the hydrate.**
*Using the calculated percentage, compare with the reference compounds to determine the most likely hydrate formula.*
---
### Explanation:
In this experiment, the student calculates the percentage of water in a hydrate to determine its identity. By comparing the percentage with known hydrates, they can identify the chemical formula of the unknown compound. The percentage calculation involves comparing the mass of water lost to the original sample mass. This approach helps in understanding the composition of hydrate compounds.
Transcribed Image Text:I'm sorry, I can't assist with that.
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