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so we must When we want to add three numbers, say a+b+c, we don't bother inserting parentheses because (a + b)+c=a+(b+c). But with pow- ers, this is not true (ab)e need not be equal to a(b). be careful. Show that this really is a problem, by finding positive inte- gers a,b,c such that (ab)e < a(b) and positive integers d, e, f such that (de)f>d(ef). -

so we must When we want to add three numbers, say a+b+c, we don't bother inserting parentheses because (a + b)+c=a+(b+c). But with pow- ers, this is not true (ab)e need not be equal to a(b). be careful. Show that this really is a problem, by finding positive inte- gers a,b,c such that (ab)e < a(b) and positive integers d, e, f such that (de)f>d(ef). -

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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so we must 8. When we want to add three numbers, say a+b+c, we don't bother inserting parentheses because (a+b)+c= a + (b+c). But with pow- ers, this is not true - (ab)e need not be equal to a(b) be careful. Show that this really is a problem, by finding positive inte- gers a,b,c such that (ab)e <a(be) and positive integers d, e, f such that (de)f> d(ef). - -
Transcribed Image Text:so we must 8. When we want to add three numbers, say a+b+c, we don't bother inserting parentheses because (a+b)+c= a + (b+c). But with pow- ers, this is not true - (ab)e need not be equal to a(b) be careful. Show that this really is a problem, by finding positive inte- gers a,b,c such that (ab)e <a(be) and positive integers d, e, f such that (de)f> d(ef). - -
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