So we found that the slope of the tangent line at x = 36 is 12 , and that (36, 6) is a point on the line. Substituting these values into the point-slope formula y - Yo = m(x - xo), we have y-Yo = m(x – xo) y - 6 = (x- 36) 12 Solving this for y, we can conclude that the equation of the tangent line to f(x) = Vx at x = 36 is %3D y =
So we found that the slope of the tangent line at x = 36 is 12 , and that (36, 6) is a point on the line. Substituting these values into the point-slope formula y - Yo = m(x - xo), we have y-Yo = m(x – xo) y - 6 = (x- 36) 12 Solving this for y, we can conclude that the equation of the tangent line to f(x) = Vx at x = 36 is %3D y =
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![Part 3 of 4
Using the factorization x – 36 = (/x – 6)(/x + 6), we have
9 – x^
x→36 (/x - 6)(/x + 6)
Vx – 6
mtan
lim
%3D
1
lim
(Vx
+ 6)
VI+6
X→36
= 1/12
1/12
Part 4 of 4
1
and that (36, 6) is a point on the line.
12
So we found that the slope of the tangent line at x = 36 is
%3D
Substituting these values into the point-slope formula y – Yo = m(x – x0), we have
y – Yo = m(x – xo)
y – 6 =
-(х - 36)
12
|
Solving this for y, we can conclude that the equation of the tangent line to f(x) = Vx at x = 36 is
%3D
y =](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb9c909ac-c4b4-4224-94c1-07a5b3c216fb%2F1fcbdecd-75f4-467b-a4e5-73f8ec736c1f%2F1mxdc9r_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Part 3 of 4
Using the factorization x – 36 = (/x – 6)(/x + 6), we have
9 – x^
x→36 (/x - 6)(/x + 6)
Vx – 6
mtan
lim
%3D
1
lim
(Vx
+ 6)
VI+6
X→36
= 1/12
1/12
Part 4 of 4
1
and that (36, 6) is a point on the line.
12
So we found that the slope of the tangent line at x = 36 is
%3D
Substituting these values into the point-slope formula y – Yo = m(x – x0), we have
y – Yo = m(x – xo)
y – 6 =
-(х - 36)
12
|
Solving this for y, we can conclude that the equation of the tangent line to f(x) = Vx at x = 36 is
%3D
y =
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