Answered: So the problem is im solving this…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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So the problem is im solving this textbook problem and when im doing the math im getting 271K, what am i doing wrong. I prefer paper responses instead of computer so i can really understand. im horrible at math , plz help. This is the textbook problem: A certain reaction has an activation energy of 54.0 kJ/mol. As the temperature is increased from 22 C to a higher temperature, the rate constant increases by a factor of 7.00. Calculate the higher temperature.

別
My work
In (K₁) = ( Ea ) ( ½/₂2 - 7 )
T2
In (7) = (540x1013/1) ( 1₂ -295)
T2
1.9.459 = 6995,0685 K ( 72
11.9459 = 6495,0685 K (7/7/₂2
1
6495,0685
2.995×10-4 =
1
72
64950685
+ tel:649560685
IZ
295
1
72
= 3₁6 88 5 x 10-3
-
1
3.6885×10-3
295
= 2.995× 10 -4+ 3,389 x 10-31
к
295
700
= 271K

#15.
(2) -
In
In(7.00) =
1
12
=
=
Е
1
RT₁ Т2
-
К2
k₁
textbook
=7.00, T1=295 K, Ea = 54.0 x 103 J/mol
5.4 x 104 J/mol
1
8.3145/K . mol 295K
=3.09×10-3, (Tz=324 к=51°C
T2
1
295K
-
1
Т2
=
3.00 × 10-4

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