So, P(A N B) is the probability that both dice show a 5. Of the 36 possible outcomes, there is only one outcome where this occurs, (5, 5). Therefore, P(A N B) will be equal to the probability that one of the 36 outcomes occur. We previously determined that the probability of any one of the 36 equally likely outcomes is + so, P(A N B) = ( 36 We now find P(8) the probability that the green (second) die shows a 5. The set B is as follows. B = {(1, 5), (2, 5), (3, 5), (4, 5), (5, 5), (6, 5)} There are outcomes in set 8, each with probability So, P(B) = 36 36
So, P(A N B) is the probability that both dice show a 5. Of the 36 possible outcomes, there is only one outcome where this occurs, (5, 5). Therefore, P(A N B) will be equal to the probability that one of the 36 outcomes occur. We previously determined that the probability of any one of the 36 equally likely outcomes is + so, P(A N B) = ( 36 We now find P(8) the probability that the green (second) die shows a 5. The set B is as follows. B = {(1, 5), (2, 5), (3, 5), (4, 5), (5, 5), (6, 5)} There are outcomes in set 8, each with probability So, P(B) = 36 36
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Binomial Distribution
Binomial is an algebraic expression of the sum or the difference of two terms. Before knowing about binomial distribution, we must know about the binomial theorem.
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Transcribed Image Text:So, P(A N B) is the probability that both dice show a 5. Of the 36 possible outcomes, there is only one
outcome where this occurs, (5, 5). Therefore, P(A N B) will be equal to the probability that one of the 36
outcomes occur. We previously determined that the probability of any one of the 36 equally likely outcomes is
1
So, P(A N B) =
36
We now find P(8) the probability that the green (second) die shows a 5. The set B is as follows.
B = {(1, 5), (2, 5), (3, 5), (4, 5), (5, 5), (6, 5)}
There are
outcomes in set B, each with probability So, P(B) =
36
36
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