So I ONLY need help with #1, so I was attempting to calculate Trotation & Ttransfer for #1 and NEED to know if I did my calculations correctly..........Trotation: (1/2)*(1/(10000/60))*1000 = 3ms & Ttransfer: Question 1Question 2Consider a disk with the following specifications:• Capacity: 4TBRPM: 10000Average Seek: 6msMax Transfer: 90MB/sPlease compute the following for a transfer of 512 bytes:A. TseekB. TrotationC. TtransferD. Ti/oConsider a disk with the following specifications:Capacity: 8TBRPM: 5400Average Seek: 5msMax Transfer: 140MB/sPlease compute the following for a transfer of 50MB bytes:A. TseekB. TrotationC. TtransferD. Ti/oAssume a drive has been engineered so that the max transfer rateis exactly the max rate at which the data passes under the headswhen reading sequentially. If this drive has the followingspecifications, what's the max transfer rate (in MB/s)? (show yourQuestion 3 work--I need to be able to figure out how YOU figured it out)Capacity: 10TBPlatters: 7 (double sided)RPM: 5400Tracks/platter side: 1024

According to the information given:- We have to follow the instruction in order to calculate T…

So I ONLY need help with #1, so I was attempting to calculate Trotation & Ttransfer for #1 and NEED to know if I did my calculations correctly..........Trotation: (1/2)*(1/(10000/60))*1000 = 3ms & Ttransfer:

So I ONLY need help with #1, so I was attempting to calculate Trotation & Ttransfer for #1 and NEED to know if I did my calculations correctly..........Trotation: (1/2)(1/(10000/60))1000 = 3ms & Ttransfer:

Systems Architecture

7th Edition

ISBN:9781305080195

Author:Stephen D. Burd

Publisher:Stephen D. Burd

Chapter12: Secondary Storage Management

Section: Chapter Questions

Problem 12VE

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Question A file system with 300 GByte disk uses a file descriptor with 8 direct block addresses, I indirect block address and 1 doubly indirect block address. The size of each disk block is 128 Bytes and the size of each disk block address is 8 Bytes. The maximum possible file size in this file system will be ?
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