So I am trying to write a code that will tell you if a year is a leap year or not but so far it is only acknowledging centuries (1600, 1700, 1800, etc.). Any advice on where my code seems wrong? input_year = int(input()) def is_leap_year(input_year):     if input_year % 4 == 0:         if input_year % 100 == 0:             if input_year % 400 == 0:                 return True             else:                 return False         else:             return False     else:         return False if is_leap_year(input_year):     print(input_year, '- leap year') else:     print(input_year, '- not a leap year')

Database System Concepts
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ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
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So I am trying to write a code that will tell you if a year is a leap year or not but so far it is only acknowledging centuries (1600, 1700, 1800, etc.). Any advice on where my code seems wrong?

input_year = int(input())

def is_leap_year(input_year):
    if input_year % 4 == 0:
        if input_year % 100 == 0:
            if input_year % 400 == 0:
                return True
            else:
                return False
        else:
            return False
    else:
        return False

if is_leap_year(input_year):
    print(input_year, '- leap year')
else:
    print(input_year, '- not a leap year')

Expert Solution
Step 1: Introduction

let's break down the logic of the code:

  1. Input Year: The code starts by taking user input for a year as an integer.

  2. is_leap_year Function:

    • This function checks whether a given year is a leap year or not based on the rules for leap years:
      • A year is a leap year if it is divisible by 4.
      • However, if a year is divisible by 100, it is not a leap year, unless it is also divisible by 400, in which case it is a leap year.
  3. Return Statement:

    • The function uses a single return statement to check both conditions:
      • It first checks if the year is divisible by 4 (input_year % 4 == 0).
      • Then, it checks that the year is either not divisible by 100 (input_year % 100 != 0) or it is divisible by 400 (input_year % 400 == 0). This condition ensures that years like 1700, 1800, and 1900 are not considered leap years, but years like 1600 and 2000 are.
  4. Printing the Result:

    • Finally, the code calls the is_leap_year function with the input year and prints the result. If the function returns True, it prints that it's a leap year; otherwise, it prints that it's not a leap year.

This logic correctly identifies leap years according to the rules, making it an accurate and concise way to determine leap years in Python.


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