(so far) kept up pace with population size, illustrating yet again that mathematical models are only as good as the assumptions that underlie them. 10.2.4 Exercises For the following scenarios for a population: 1) Construct a dynamic model by writing down a difference equation both in the updating function form (N(t+1) = f(N(t))) and the increment form (N(t+1)-N(t) = g(N(t))) and specify the time step; 2) find the solution of the linear difference equation with a generic initial value and check that it satisfies the difference equation by plugging the solution into your equation (in either form); 3) plug in the given initial value and predict the future. 1. Zombies have appeared in Chicago. Every day, each zombie produces 3 new zombies. Suppose that initially there is only one zombie, how many zombies will there be in 7 days? 2. Suppose hunters kill 50 deer in a national forest every hunting season, while the deer by themselves have equal birth and death rates. If there are initially 500 deer in the forest, predict how many there will be in 5 years. 3. The number of infected people in a population grows by 8% per day and those who become infected remain infected. If initially there are 8 infected, how many individuals will be infected in 45 days? 4. Suppose bacteria in a population divide in 2 every hour and 90% of the current population dies after reproduction, not including the new offspring. If the population initially has 10 million bacteria, predict how many there will be in 12 hours. 5. In a rabbit population, each pair produces 1.2 offspring every year (i.e. 0.6 per capita) and the adults have a 0.5 annual death rate after reproduction (and assume the whole population is paired up into mating pairs.) If initially there are 100 rabbits, predict how many there will be in 5 years. 6. Consider the same rabbit population, but now a python that lives nearby eats exactly 1 rabbit a month. If initially there are 100 rabbits, how many do you predict will be in 10 years? 162

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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Number 9!! 

J
5
T
13
오
As we see, there are only two options for solution of linear difference equations: ever-faster
growth or decay to zero or another constant value. The exponential growth of populations
is also known as Malthusian after the early population modeler Thomas Malthus. He used
a simple population model with constant growth rate to predict demographic disaster due to
the exponentially increasing population outstripping the growth in food production. In fact,
human population has not been growing with a constant birth rate, and food production has
(so far) kept up pace with population size, illustrating yet again that mathematical models are
only as good as the assumptions that underlie them.
10.2.4 Exercises
For the following scenarios for a population: 1) Construct a dynamic model by writing down a
difference equation both in the updating function form (N(t+1) = f(N(t))) and the increment
form (N(t+1) - N(t) = g(N(t))) and specify the time step; 2) find the solution of the linear
difference equation with a generic initial value and check that it satisfies the difference equation
by plugging the solution into your equation (in either form); 3) plug in the given initial value
and predict the future.
1. Zombies have appeared in Chicago. Every day, each zombie produces 3 new zombies.
Suppose that initially there is only one zombie, how many zombies will there be in 7
days?
2. Suppose hunters kill 50 deer in a national forest every hunting season, while the deer by
themselves have equal birth and death rates. If there are initially 500 deer in the forest,
predict how many there will be in 5 years.
3. The number of infected people in a population grows by 8% per day and those who
become infected remain infected. If initially there are 8 infected, how many individuals
will be infected in 45 days?
4. Suppose bacteria in a population divide in 2 every hour and 90% of the current population
dies after reproduction, not including the new offspring. If the population initially has
10 million bacteria, predict how many there will be in 12 hours.
5. In a rabbit population, each pair produces 1.2 offspring every year (i.e. 0.6 per capita)
and the adults have a 0.5 annual death rate after reproduction (and assume the whole
population is paired up into mating pairs.) If initially there are 100 rabbits, predict how
many there will be in 5 years.
6. Consider the same rabbit population, but now a python that lives nearby eats exactly 1
rabbit a month. If initially there are 100 rabbits, how many do you predict will be in 10
years?
162
1
Transcribed Image Text:J 5 T 13 오 As we see, there are only two options for solution of linear difference equations: ever-faster growth or decay to zero or another constant value. The exponential growth of populations is also known as Malthusian after the early population modeler Thomas Malthus. He used a simple population model with constant growth rate to predict demographic disaster due to the exponentially increasing population outstripping the growth in food production. In fact, human population has not been growing with a constant birth rate, and food production has (so far) kept up pace with population size, illustrating yet again that mathematical models are only as good as the assumptions that underlie them. 10.2.4 Exercises For the following scenarios for a population: 1) Construct a dynamic model by writing down a difference equation both in the updating function form (N(t+1) = f(N(t))) and the increment form (N(t+1) - N(t) = g(N(t))) and specify the time step; 2) find the solution of the linear difference equation with a generic initial value and check that it satisfies the difference equation by plugging the solution into your equation (in either form); 3) plug in the given initial value and predict the future. 1. Zombies have appeared in Chicago. Every day, each zombie produces 3 new zombies. Suppose that initially there is only one zombie, how many zombies will there be in 7 days? 2. Suppose hunters kill 50 deer in a national forest every hunting season, while the deer by themselves have equal birth and death rates. If there are initially 500 deer in the forest, predict how many there will be in 5 years. 3. The number of infected people in a population grows by 8% per day and those who become infected remain infected. If initially there are 8 infected, how many individuals will be infected in 45 days? 4. Suppose bacteria in a population divide in 2 every hour and 90% of the current population dies after reproduction, not including the new offspring. If the population initially has 10 million bacteria, predict how many there will be in 12 hours. 5. In a rabbit population, each pair produces 1.2 offspring every year (i.e. 0.6 per capita) and the adults have a 0.5 annual death rate after reproduction (and assume the whole population is paired up into mating pairs.) If initially there are 100 rabbits, predict how many there will be in 5 years. 6. Consider the same rabbit population, but now a python that lives nearby eats exactly 1 rabbit a month. If initially there are 100 rabbits, how many do you predict will be in 10 years? 162 1
J
5
T
13
오
As we see, there are only two options for solution of linear difference equations: ever-faster
growth or decay to zero or another constant value. The exponential growth of populations
is also known as Malthusian after the early population modeler Thomas Malthus. He used
a simple population model with constant growth rate to predict demographic disaster due to
the exponentially increasing population outstripping the growth in food production. In fact,
human population has not been growing with a constant birth rate, and food production has
(so far) kept up pace with population size, illustrating yet again that mathematical models are
only as good as the assumptions that underlie them.
10.2.4 Exercises
For the following scenarios for a population: 1) Construct a dynamic model by writing down a
difference equation both in the updating function form (N(t+1) = f(N(t))) and the increment
form (N(t+1) - N(t) = g(N(t))) and specify the time step; 2) find the solution of the linear
difference equation with a generic initial value and check that it satisfies the difference equation
by plugging the solution into your equation (in either form); 3) plug in the given initial value
and predict the future.
1. Zombies have appeared in Chicago. Every day, each zombie produces 3 new zombies.
Suppose that initially there is only one zombie, how many zombies will there be in 7
days?
2. Suppose hunters kill 50 deer in a national forest every hunting season, while the deer by
themselves have equal birth and death rates. If there are initially 500 deer in the forest,
predict how many there will be in 5 years.
3. The number of infected people in a population grows by 8% per day and those who
become infected remain infected. If initially there are 8 infected, how many individuals
will be infected in 45 days?
4. Suppose bacteria in a population divide in 2 every hour and 90% of the current population
dies after reproduction, not including the new offspring. If the population initially has
10 million bacteria, predict how many there will be in 12 hours.
5. In a rabbit population, each pair produces 1.2 offspring every year (i.e. 0.6 per capita)
and the adults have a 0.5 annual death rate after reproduction (and assume the whole
population is paired up into mating pairs.) If initially there are 100 rabbits, predict how
many there will be in 5 years.
6. Consider the same rabbit population, but now a python that lives nearby eats exactly 1
rabbit a month. If initially there are 100 rabbits, how many do you predict will be in 10
years?
162
1
Transcribed Image Text:J 5 T 13 오 As we see, there are only two options for solution of linear difference equations: ever-faster growth or decay to zero or another constant value. The exponential growth of populations is also known as Malthusian after the early population modeler Thomas Malthus. He used a simple population model with constant growth rate to predict demographic disaster due to the exponentially increasing population outstripping the growth in food production. In fact, human population has not been growing with a constant birth rate, and food production has (so far) kept up pace with population size, illustrating yet again that mathematical models are only as good as the assumptions that underlie them. 10.2.4 Exercises For the following scenarios for a population: 1) Construct a dynamic model by writing down a difference equation both in the updating function form (N(t+1) = f(N(t))) and the increment form (N(t+1) - N(t) = g(N(t))) and specify the time step; 2) find the solution of the linear difference equation with a generic initial value and check that it satisfies the difference equation by plugging the solution into your equation (in either form); 3) plug in the given initial value and predict the future. 1. Zombies have appeared in Chicago. Every day, each zombie produces 3 new zombies. Suppose that initially there is only one zombie, how many zombies will there be in 7 days? 2. Suppose hunters kill 50 deer in a national forest every hunting season, while the deer by themselves have equal birth and death rates. If there are initially 500 deer in the forest, predict how many there will be in 5 years. 3. The number of infected people in a population grows by 8% per day and those who become infected remain infected. If initially there are 8 infected, how many individuals will be infected in 45 days? 4. Suppose bacteria in a population divide in 2 every hour and 90% of the current population dies after reproduction, not including the new offspring. If the population initially has 10 million bacteria, predict how many there will be in 12 hours. 5. In a rabbit population, each pair produces 1.2 offspring every year (i.e. 0.6 per capita) and the adults have a 0.5 annual death rate after reproduction (and assume the whole population is paired up into mating pairs.) If initially there are 100 rabbits, predict how many there will be in 5 years. 6. Consider the same rabbit population, but now a python that lives nearby eats exactly 1 rabbit a month. If initially there are 100 rabbits, how many do you predict will be in 10 years? 162 1
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