So D 2e/y dA where D = {(x, y)|1 ≤ y ≤ 2, y ≤ x ≤ y³} What is the value of 2e4 Oe-2e 4e Oe-4e None of the above

Q: find extreme Value of function fex, y) = x°t 3xy?-3x²-3y=t7 1

A: Given:  fx,y=x3+3xy2-3x2-3y2+7 ⇒fx=3x2+3y2-6x, fy=6xy-6y To find extreme points put fy=0, fx=0…

Q: e dy dx У-х+1 У-х +5

A:

Q: Evaluate " " So s L dz dx dy rvZ c3y (8-x²-y² Jx²+3y²

A:

Q: 1. Find 2(3z + 4)² dz.

A:

Q: dy Ex2: find for the following functions: dx a) y = (x² + 1)5 b) y = [(5-x)(4- 2x)]? c) y = (2x3 –…

A: According to guidelines we should have been able to solve only three subpart of the question

Q: 2- Show that: -1 xb-1 In x dx b2

A: See the attachment

Q: S 1 (x + ²)² + ( √ 39 ) ² 2 dx

A:

Q: 3/4y +1 dy 2. Evaluate 0,

A: Given: ∫0234y+1dy Substitute, 4y+1=u dudy=4dy=14du =34∫udu ...........(1)

Q: Compute 3+r+1 dx x2

A: Given : ∫233x2+2x+1x2dx

Q: Show that: -1 xb-1 In x dx b2 2-

A: we use integration by parts

Q: dy =Log. Loc

A: Using logarithmic property we can solve this problem.

Q: 3. fz √z dz 4. (2x² 3x + 5) dx -

A: 3. ∫zzdz4. ∫2x2-3x+5dx

Q: dr Find if r (x) = 9x 2 + 5x – 3. dx

A: Given,            r(x) = 9x2 + 5x - 3

Q: 11. Evaluate 9-y² LS [[V²=2³² (x² + y²) ² dx dy -3 0

A: We need to evaluate the double integral given by :

Q: If 2x = xy + y2, then A. C. -2 + y x + 2y (2-y) x + 2y dx 11 B. D. -(2 + y) x + 2y -(-2+ y) x + 2xy

A:

Q: dx = 2x - 1 x³+3x + C x2 +C -- 3+C 2. 6. In x +C In x +C

A:

Q: 8tan4x dx. Q. S 3 None 8log|sec4x| + c 3 2log|sec4x| + c 3 2log|sec4x| + c 4

A:

Q: 1-y Q2: Evaluate fo y²(x² + y²)dx dy -1

A:

Q: 11x+8 1. S x²+x-6 dx

A:

Q: 2. Find b such that dx 1+x2 3

A: