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So, converted to az interval, we wish to find P(0.68 < z< 1.14). Recall that since the z value is between two different values, we will need to subtract the table areas for z, = 0.68 from the table area for z, = 1.14. Use this table to determine P(z < 0.68) and P(z < 1.14). Substitute these values into the formula to find the probability. (Round your answer to three decimal places.) P(0.68 < z < 1.14) = P(z < 1.14) - P(z < 0.68)

So, converted to az interval, we wish to find P(0.68 < z< 1.14). Recall that since the z value is between two different values, we will need to subtract the table areas for z, = 0.68 from the table area for z, = 1.14. Use this table to determine P(z < 0.68) and P(z < 1.14). Substitute these values into the formula to find the probability. (Round your answer to three decimal places.) P(0.68 < z < 1.14) = P(z < 1.14) - P(z < 0.68)

A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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So, converted to a z interval, we wish to find P(0.68 < z < 1.14). Recall that since the z value is between two different values, we will need to subtract the table areas for = 0.68 from the table area for z, = 1.14. Use this table to determine P(z < 0.68) and P(z < 1.14). Substitute these values into the formula to find the probability. (Round your answer to three decimal places.) P(0.68 < z< 1.14) = P(z < 1.14) – P(z < 0.68) %3D
Transcribed Image Text:So, converted to a z interval, we wish to find P(0.68 < z < 1.14). Recall that since the z value is between two different values, we will need to subtract the table areas for = 0.68 from the table area for z, = 1.14. Use this table to determine P(z < 0.68) and P(z < 1.14). Substitute these values into the formula to find the probability. (Round your answer to three decimal places.) P(0.68 < z< 1.14) = P(z < 1.14) – P(z < 0.68) %3D
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