Snoopy Services is taking care of 10 dogs. Four of them are beagles, two are rottweilers, and four are corgis. How many ways can all the dogs be lined up for a photograph? How many ways can 7 of the dogs be lined up for a photograph? 120 How many ways can all the dogs be lined up for a photograph, if all the beagles must be next to each other? How many ways can all the dogs be lined up for a photograph, if all the dogs of a similar breed must be next to each other? (All the beagles are together, all the rottweilers are together, and all the corgis are together)

A First Course in Probability (10th Edition)
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Author:Sheldon Ross
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Chapter1: Combinatorial Analysis
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Snoopy Services is taking care of 10 dogs. Four of them
are beagles, two are rottweilers, and four are corgis.
How many ways can all the dogs be lined up for a
photograph?
How many ways can 7 of the dogs be lined up for a
photograph?
120
How many ways can all the dogs be lined up for a
photograph, if all the beagles must be next to each
other?
How many ways can all the dogs be lined up for a
photograph, if all the dogs of a similar breed must be
next to each other? (All the beagles are together, all
the rottweilers are together, and all the corgis are
together)
How many ways can all the dogs be lined up for a
photograph if all the beagles must be kept separate
from each other?
Transcribed Image Text:Snoopy Services is taking care of 10 dogs. Four of them are beagles, two are rottweilers, and four are corgis. How many ways can all the dogs be lined up for a photograph? How many ways can 7 of the dogs be lined up for a photograph? 120 How many ways can all the dogs be lined up for a photograph, if all the beagles must be next to each other? How many ways can all the dogs be lined up for a photograph, if all the dogs of a similar breed must be next to each other? (All the beagles are together, all the rottweilers are together, and all the corgis are together) How many ways can all the dogs be lined up for a photograph if all the beagles must be kept separate from each other?
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