Balance the following chemical equation (if necessary): **Chemical Reaction Equation**The given chemical equation represents the decomposition of tin(IV) perchlorate (Sn(ClO₄)₄). It can be transcribed as follows:\[ \text{Sn(ClO}_4\text{)}_4(s) \rightarrow \text{SnCl}_4(s) + \text{O}_2(g) \]**Explanation:**- **Reactant:** - Sn(ClO₄)₄(s) is solid tin(IV) perchlorate. - **Products:** - SnCl₄(s) is solid tin(IV) chloride. - O₂(g) is gaseous oxygen.This equation illustrates the breakdown of the tin(IV) perchlorate compound into tin(IV) chloride and oxygen gas upon decomposition. The states of matter are indicated in parentheses where (s) denotes solid and (g) denotes gas.

Answered: Sn(CIO:)«(s) → SnCl:(s) + O:(g)

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Chemistry

Sn(CIO:)«(s) → SnCl:(s) + O:(g)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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