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Sn(CIO:)«(s) → SnCl:(s) + O:(g)

Sn(CIO:)«(s) → SnCl:(s) + O:(g)

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Balance the following chemical equation (if necessary):

 

**Chemical Reaction Equation** The given chemical equation represents the decomposition of tin(IV) perchlorate (Sn(ClO₄)₄). It can be transcribed as follows: \[ \text{Sn(ClO}_4\text{)}_4(s) \rightarrow \text{SnCl}_4(s) + \text{O}_2(g) \] **Explanation:** - **Reactant:** - Sn(ClO₄)₄(s) is solid tin(IV) perchlorate. - **Products:** - SnCl₄(s) is solid tin(IV) chloride. - O₂(g) is gaseous oxygen. This equation illustrates the breakdown of the tin(IV) perchlorate compound into tin(IV) chloride and oxygen gas upon decomposition. The states of matter are indicated in parentheses where (s) denotes solid and (g) denotes gas.
Transcribed Image Text:**Chemical Reaction Equation** The given chemical equation represents the decomposition of tin(IV) perchlorate (Sn(ClO₄)₄). It can be transcribed as follows: \[ \text{Sn(ClO}_4\text{)}_4(s) \rightarrow \text{SnCl}_4(s) + \text{O}_2(g) \] **Explanation:** - **Reactant:** - Sn(ClO₄)₄(s) is solid tin(IV) perchlorate. - **Products:** - SnCl₄(s) is solid tin(IV) chloride. - O₂(g) is gaseous oxygen. This equation illustrates the breakdown of the tin(IV) perchlorate compound into tin(IV) chloride and oxygen gas upon decomposition. The states of matter are indicated in parentheses where (s) denotes solid and (g) denotes gas.
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Step 1

We need to balance the given equation. 

Balanced chemical equation contain equal number of atoms on left hand side and right hand side of each element.

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