Sleeping outlier: A simple random sample of elght college freshmen were asked how many hours of sleep they typically got per night. The results were 8.5 24 8.5 8. 7.5 6.5 Send data to Excel Notice that one joker said that he sleeps 24 a day. Part: 0/3 Part 1 of 3 (a) The data contain an outlier that is clearly a mistake. Eliminate the outlier, then construct a 99% confidence interval for the mean amount of sleep from the remaining values. Round the answers to at least two decimal places. A 99% confidence interval for the mean amount of sleep from the remaining values is

Sleeping outlier: A simple random sample of elght college freshmen were asked how many hours of sleep they typically got per night. The results were 8.5 24 8.5 8. 7.5 6.5 Send data to Excel Notice that one joker said that he sleeps 24 a day. Part: 0/3 Part 1 of 3 (a) The data contain an outlier that is clearly a mistake. Eliminate the outlier, then construct a 99% confidence interval for the mean amount of sleep from the remaining values. Round the answers to at least two decimal places. A 99% confidence interval for the mean amount of sleep from the remaining values is

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A government agency computed the proportion of U.S. residents who lived in each of four geographic regions in a particular year. Then a simple random sample was drawn of 1000 people living in the United States in the current year. The following table presents the results. Region Past YearProportion ObservedCounts Northeast 0.171 150 Midwest 0.245 235 South 0.357 398 West 0.227 217 Send data to Excel Can you conclude that the proportions of people living in the various regions changed between the current year and the past year? Use the 0.05 level of significance and the P-value method with the TI-84 Plus calculator. What the P value?
You may need to use the appropriate technology to answer this question. Suppose a company surveyed the work preferences and atitudes of 1,006 working adults spread over three generations: baby boomers, Generation X, and millennials. In one question, individuals were asked if they would leave their current job to make more money at another Job. The sample data are summarized in the following table. Generation Leave Job for More Money? Baby Boomer Generation X Millennial Yes 124 154 167 No 202 185 174 Conduct a test of independence to determine whether interest in leaving a current job for more money is independent of employee generation State the null and aiternative hypotheses Hg Interest in leaving job for more money is independent of the employee generation H, Interest in leaving job for more money is not independent of the employee generation. OH Interest in leaving job for mere money is mutually excusive of the employee generation H, Interest in leaving job for more money is not…
According to the financial reports by Snapchat, the average daily user of Snapchat created 19 messages, or "snaps," per day in Q3 2017. A college student wants to find out if the number of Snapchat messages has changed since Q3 2017 and creates a random sample using information from students on her campus for the current semester, with the accompanying results. Complete parts a through Click the icon to view the daily snaps data. C. a. Using a = 0.01, test the hypothesis that the number of Snapchats sent by the average Snapchat user has not changed since Q3 2017. Determine the null and alternative hypotheses. Hot = 19 19 H₁: (Type integers or decimals. Do not round.) Determine the appropriate critical value. Select the correct choice below and fill in the answer box within your choice. (Round to three decimal places as needed.) O A. O B. -ta= OC. ±¹/2 t = t Daily Snaps G 22 13 9 18 15 33 8 23 27 27 22 31 20 16 19 33 31 5 Print 15 D 21 Done - X
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A television station wishes to study the relationship between viewership of its 11 p.m. news program and viewer age (18 years or less, 19 to 35, 36 to 54, 55 or older). A sample of 250 television viewers in each age group is randomly selected, and the number who watch the station’s 11 p.m. news is found for each sample. The results are given in the table below. Age Group Watch11 p.m. News? 18 or less 19 to 35 36 to 54 55 or Older Total Yes 37 46 59 83 225 No 213 204 191 167 775 Total 250 250 250 250 1,000 (a) Let p1, p2, p3, and p4 be the proportions of all viewers in each age group who watch the station’s 11 p.m. news. If these proportions are equal, then whether a viewer watches the station’s 11 p.m. news is independent of the viewer’s age group. Therefore, we can test the null hypothesis H0 that p1, p2, p3, and p4 are equal by carrying out a chi-square test for independence. Perform this test by setting α = .05. (Round your answer to 3 decimal places.)…
In a study of computer use, 1000 randomly selected Canadian Internet users were asked how much time they spend using the Internet in a typical week. The mean of the sample observations was 12.6 hours.
A television station wishes to study the relationship between viewership of its 11 p.m. news program and viewer age (18 years or less, 19 to 35, 36 to 54, 55 or older). A sample of 250 television viewers in each age group is randomly selected, and the number who watch the station’s 11 p.m. news is found for each sample. The results are given in the table below. Age Group Watch11 p.m. News? 18 or less 19 to 35 36 to 54 55 or Older Total Yes 49 59 61 84 253 No 201 191 189 166 747 Total 250 250 250 250 1,000 (a) Let p1, p2, p3, and p4 be the proportions of all viewers in each age group who watch the station’s 11 p.m. news. If these proportions are equal, then whether a viewer watches the station’s 11 p.m. news is independent of the viewer’s age group. Therefore, we can test the null hypothesis H0 that p1, p2, p3, and p4 are equal by carrying out a chi-square test for independence. Perform this test by setting α = .05. (Round your answer to 3 decimal places.)…
Foxbees magazine published data on the best small firms in 2012. These publicly traded firms have a stock price of at least $5 per share and have reported annual revenue between $5 million and $1 billion. The data below shows the ages of the corporate CEOS for a random sample of these firms. 49 67 59 48 45 49 39 44 37 38 48 38 43 48 62 74 70 58 58 40 74 35 36 54 38 45 54 55 64 75 69 36 55 72 69 60 40 64 39 59 74 52 40 49 38 38 74 50 55 50 R vector Copy to clipboard a) What is the mean of the sample? (Round to 4 decimal places) b) What is the standard deviation of the sample mean or the standard error? (Round to 4 decimal places) c) What is the sample size? (Round to whole number)
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1. A scientist is studying the effect of exercise on blood pressure. He studies 50 people who exercise regularly to find out whether their blood pressures are low, average, or high. This is an example of a(n): Answer choices: sample survey. observational study. experiment.
Suppose a random sample of 800 athletes from the college are asked what their major is. The table below shows the results of the survey. Observed Frequencies of Majors from the Sample Observed Frequency Outcome Math/Science 256 Arts & Humanities 190 Business & Economics 153 Other 201 The distribution of majors at the college is shown in the second column of the table below. Fill in the expected frequencies. (Round to the nearest whole number). Frequencies of Majors at the College Expected Percent Outcome Expected Frequency Math/Science 18 Arts & Humanities 29 Business & Economics 25
You are told that the proportion p-hat of those who answered "yes" to a poll about internet use is p-hat = 0.70, and the standard error of the proportion is 0.0458. What was the sample size?