Sla 1 z dx |(25 – x²)3/2]

Q: Evaluate 3 | ((2 – 1)32, (3 + t)2, 1)dx. 3/2 3/2 -3

A:

Q: x³ dx 9+x* 1.

A:

Q: Find the cost function for the marginal cost function. 0.02x. C'(x) = 0.07 e fixed cost is $5 C(x) =

A: To solve the integral

Q: (I+x²)d (l-x²) Vi+

A:

Q: 7. Use substitution to evaluate ſ 2x(4 – x²) dx.

A:

Q: 1 dx (2x + 1)4

A: We will use concept of improper integral here.

Q: dx (9 – 4.x²)³/2 2,3/2

A: Given: The integral is ∫dx9-4x232. To find: Value of the integral.

Q: 4 dx 16 + x2 -4

A: To find: The integration of ∫-44dx16+x2. Concept used: Integration formula: ∫dxa2+x2=1atan-1xa

Q: (2x + 1)1º x² dx

A:

Q: x2+1 - dx x4-x²+1

A:

Q: Evaluate: d/dx [(x/7) + 7]

A:

Q: •B Find 2xVx- 5 dx, where B > 3.

A:

Q: dx 4+x*

A: Proceed as shown below...

Q: 1 dx x² + 6x + 9

A: We have to evaluate the integral: ∫1x2+6x+9dx Rewriting the integral,…

Q: Show that (xcos(2x)dx=. A-2 8

A: LetI=∫0π4xcos2xdxPut 2x=udifferentiate on both side2dx=dudx=du2As x→0 then u→0As x→π4 then…

Q: 5x dx (x² + 3)2/3

A: We will use a substitution to solve the equation.

Q: .2 dx 6. (x-1)3

A:

Q: Compute 3+r+1 dx x2

A: Given : ∫233x2+2x+1x2dx

Q: Evaluate.

A:

Q: -dx x +1 2 5.

A:

Q: (1 +Iпx) dx x3

A: The given integral is ∫1+ln xx3dx. Here, u=1+ln x  and  v=1x3.

Q: 1 10. dx x² Vx² – 4 -

A:

Q: Evaluate x(x2 + 1)3 dx.

A: Given ∫x(x2+1)3dx

Q: 4 7 dx x2 – 9

A: Given, ∫047x2-9dx

Q: x2 + 1 dx (x2 – 2x + 2)2

A: Explanation of the solution is given below..

Q: 00 x3 dx (x²+1)² it

A:

Q: 2x² − x +4 x³ + 4x Evaluate [ [20 dx.

A: Evaluate