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Sketching a Function A Sketch the graph of a single function f(x) that satisfies all of the following conditions: 1. The domain of f is (-∞0, 0) U (0,00) 2. lim f(x) = -2 2 3. The only vertical asymptote that f has is at x = -3 4. lim f(x) = 0, but f is not continuous at x = -1 24-1 5. f(3) = 1, lim f(x) = 1, but f is not continuous at x = 3 +31 6. lim f(x) = f(5) 2-5 Give a written justification for why your graph meets the conditions above. Additionally, remember that your graph is supposed to be a graph of a function. Functions all have to pass a certain test!

Sketching a Function A Sketch the graph of a single function f(x) that satisfies all of the following conditions: 1. The domain of f is (-∞0, 0) U (0,00) 2. lim f(x) = -2 2 3. The only vertical asymptote that f has is at x = -3 4. lim f(x) = 0, but f is not continuous at x = -1 24-1 5. f(3) = 1, lim f(x) = 1, but f is not continuous at x = 3 +31 6. lim f(x) = f(5) 2-5 Give a written justification for why your graph meets the conditions above. Additionally, remember that your graph is supposed to be a graph of a function. Functions all have to pass a certain test!

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Sketching a Function A Sketch the graph of a single function f (x) that satisfies all of the following conditions: 1. The domain of f is (-∞0, 0) U (0, ∞) 2. lim f(x) = -2 x→2 3. The only vertical asymptote that f has is at x = -3 4. lim f(x) = 0, but f is not continuous at x = -1 5. f(3) = 1, lim f(x) = 1, but f is not continuous at x = 3 x 3 6. lim f(x) = f(5) x 5 Give a written justification for why your graph meets the conditions above. Additionally, remember that your graph is supposed to be a graph of a function. Functions all have to pass a certain test!
Transcribed Image Text:Sketching a Function A Sketch the graph of a single function f (x) that satisfies all of the following conditions: 1. The domain of f is (-∞0, 0) U (0, ∞) 2. lim f(x) = -2 x→2 3. The only vertical asymptote that f has is at x = -3 4. lim f(x) = 0, but f is not continuous at x = -1 5. f(3) = 1, lim f(x) = 1, but f is not continuous at x = 3 x 3 6. lim f(x) = f(5) x 5 Give a written justification for why your graph meets the conditions above. Additionally, remember that your graph is supposed to be a graph of a function. Functions all have to pass a certain test!
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