Sketch the region whose area is given by the definite integral. Then use a geometric formula to evaluate the integral (a > 0, r > 0). 1₁√9-x²0x dx Step 1 Sketch the region whose area is given by the definite integral. Step 2 x² dx -3 -2 -1 y 6 5 4 2 1 1 Note that the region given by the definite integral 2 Livo 3 X 9x² dx is a semicircle of radius

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Question
Sketch the region whose area is given by the definite integral. Then use a geometric formula to evaluate the integral (a > 0, r > 0).
3
[²√9-x² dx
Step 1
Sketch the region whose area is given by the definite integral.
Step 2
13
3
9 - x² dx
-3 -2
7
-1
y
Submit Skip (you cannot come back)
5
4
2
Note that the region given by the definite integral
1 2 3
3
Bvo-x2a
X
9 - x² dx is a semicircle of radius
Transcribed Image Text:Sketch the region whose area is given by the definite integral. Then use a geometric formula to evaluate the integral (a > 0, r > 0). 3 [²√9-x² dx Step 1 Sketch the region whose area is given by the definite integral. Step 2 13 3 9 - x² dx -3 -2 7 -1 y Submit Skip (you cannot come back) 5 4 2 Note that the region given by the definite integral 1 2 3 3 Bvo-x2a X 9 - x² dx is a semicircle of radius
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**Educational Explanation**

To determine the area of a region using calculus, consider the following steps:

### Integral Problem Statement
- The goal is to evaluate the definite integral:
  \[
  \int_{-3}^{3} \sqrt{9 - x^2} \, dx
  \]

### Step 1: Sketch the Region
- The integral represents the area under the curve given by \( y = \sqrt{9 - x^2} \).
- Sketch this curve as the top half of a circle centered at the origin with radius 3.
- The shaded region depicts a semicircle from \( x = -3 \) to \( x = 3 \).

### Graph Explanation
- The graph shows a semicircle with a radius of 3, spanning horizontally from \(-3\) to \(3\) along the x-axis.
- The y-axis ranges from 0 to 3, representing the height of the semicircle.

### Step 2: Interpretation
- Recognize that the region specified by the integral \(\int_{-3}^{3} \sqrt{9 - x^2} \, dx\) is a semicircle with radius 3.

### Step 3: Calculation Using Geometry
- To find the area of the semicircle, use the formula:
  \[
  \text{Area of a semicircle} = \frac{1}{2} \pi r^2
  \]
- Here, \( r = 3 \).

- Complete the formula to find the area of the semicircle:
  \[
  \frac{1}{2} \pi \times 3^2
  \]

### Conclusion
Submit your answer to verify the area calculation is correct. This involves basic integration and geometric understanding of circles.
Transcribed Image Text:**Educational Explanation** To determine the area of a region using calculus, consider the following steps: ### Integral Problem Statement - The goal is to evaluate the definite integral: \[ \int_{-3}^{3} \sqrt{9 - x^2} \, dx \] ### Step 1: Sketch the Region - The integral represents the area under the curve given by \( y = \sqrt{9 - x^2} \). - Sketch this curve as the top half of a circle centered at the origin with radius 3. - The shaded region depicts a semicircle from \( x = -3 \) to \( x = 3 \). ### Graph Explanation - The graph shows a semicircle with a radius of 3, spanning horizontally from \(-3\) to \(3\) along the x-axis. - The y-axis ranges from 0 to 3, representing the height of the semicircle. ### Step 2: Interpretation - Recognize that the region specified by the integral \(\int_{-3}^{3} \sqrt{9 - x^2} \, dx\) is a semicircle with radius 3. ### Step 3: Calculation Using Geometry - To find the area of the semicircle, use the formula: \[ \text{Area of a semicircle} = \frac{1}{2} \pi r^2 \] - Here, \( r = 3 \). - Complete the formula to find the area of the semicircle: \[ \frac{1}{2} \pi \times 3^2 \] ### Conclusion Submit your answer to verify the area calculation is correct. This involves basic integration and geometric understanding of circles.
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