Sketch the region that corresponds to the given inequalities. (image attached of the question) x  +  y  ≥  9 x      ≤  10     y  ≤  14 x ≥ 0, y ≥ 0     Say whether the region is bounded or unbounded. The region is bounded.The region is unbounded.       Find the coordinates of all corner points (if any). (Order your answers from smallest to largest x, then from smallest to largest y. If an answer does not exist, enter DNE.)

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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Sketch the region that corresponds to the given inequalities. (image attached of the question)
x  +  y  ≥  9
x      ≤  10
    y  ≤  14
x ≥ 0, y ≥ 0
 
 
Say whether the region is bounded or unbounded.
The region is bounded.The region is unbounded.    
 
Find the coordinates of all corner points (if any). (Order your answers from smallest to largest x, then from smallest to largest y. If an answer does not exist, enter DNE.)
(xy) = 
 
(xy) = 
 
(xy) =  
 
 
(xy) = 
 
(xy) =
 
 
 
 
 
 
The problem requires sketching the region that corresponds to a set of inequalities:

1. \(x + y \geq 9\)
2. \(x \leq 10\)
3. \(y \leq 14\)
4. \(x \geq 0\), \(y \geq 0\)

There are four different graphs provided. Each graph is a coordinate plane with:

- The x-axis ranging from \(-5\) to \(20\).
- The y-axis ranging from \(-20\) to \(20\).
- A highlighted blue solution set region.

**Graph Analysis:**

1. **First Graph:**
   - The solution set is shown in blue, primarily in the first quadrant.
   - Boundaries:
     - A vertical line at \(x = 10\)
     - A horizontal line at \(y = 14\)
     - A diagonal line from \((0,9)\) to \((9,0)\), representing \(x + y = 9\)

2. **Second Graph:**
   - Similar to the first graph but different shading within the solution.
   - Boundaries:
     - Identical to the first graph.

3. **Third Graph:**
   - Solution set is altered to a different section of the coordinate plane.
   - Boundaries:
     - Same constraints as the previous graphs.

4. **Fourth Graph:**
   - Solution set moved again.
   - Boundaries remain unchanged; only shaded area representing the solution set moves.

**Other Information:**

There's a question at the bottom to determine if the region is bounded or unbounded. Additionally, there's a task to find the coordinates of all corner points in the region, in increasing order of \(x\) and \(y\), specifying that if an answer doesn't exist, enter "DNE."

Each corner point can be found by solving the inequalities simultaneously to determine points of intersection:

- **(\(x, y\)) =** 
- **(\(x, y\)) =** 
- **(\(x, y\)) =** 
- **(\(x, y\)) =** 
- **(\(x, y\)) =**
Transcribed Image Text:The problem requires sketching the region that corresponds to a set of inequalities: 1. \(x + y \geq 9\) 2. \(x \leq 10\) 3. \(y \leq 14\) 4. \(x \geq 0\), \(y \geq 0\) There are four different graphs provided. Each graph is a coordinate plane with: - The x-axis ranging from \(-5\) to \(20\). - The y-axis ranging from \(-20\) to \(20\). - A highlighted blue solution set region. **Graph Analysis:** 1. **First Graph:** - The solution set is shown in blue, primarily in the first quadrant. - Boundaries: - A vertical line at \(x = 10\) - A horizontal line at \(y = 14\) - A diagonal line from \((0,9)\) to \((9,0)\), representing \(x + y = 9\) 2. **Second Graph:** - Similar to the first graph but different shading within the solution. - Boundaries: - Identical to the first graph. 3. **Third Graph:** - Solution set is altered to a different section of the coordinate plane. - Boundaries: - Same constraints as the previous graphs. 4. **Fourth Graph:** - Solution set moved again. - Boundaries remain unchanged; only shaded area representing the solution set moves. **Other Information:** There's a question at the bottom to determine if the region is bounded or unbounded. Additionally, there's a task to find the coordinates of all corner points in the region, in increasing order of \(x\) and \(y\), specifying that if an answer doesn't exist, enter "DNE." Each corner point can be found by solving the inequalities simultaneously to determine points of intersection: - **(\(x, y\)) =** - **(\(x, y\)) =** - **(\(x, y\)) =** - **(\(x, y\)) =** - **(\(x, y\)) =**
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