Sketch the region that corresponds to the given inequalities, say whether the region is bounded or unbounded, and find the coordinates of all corner points (if any). x + y 2 5 < 10 y< 8 x> 0, y > 0
Sketch the region that corresponds to the given inequalities, say whether the region is bounded or unbounded, and find the coordinates of all corner points (if any). x + y 2 5 < 10 y< 8 x> 0, y > 0
Intermediate Algebra
10th Edition
ISBN:9781285195728
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter7: Equations And Inequalities In Two Variables
Section7.2: Linear Inequalities In Two Variables
Problem 37.3PS
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![### Sketching the Feasible Region for Given Inequalities
To determine the region that corresponds to the given inequalities, we'll follow these steps:
1. **Identify the inequalities:**
* \( x + y \geq 5 \)
* \( x \leq 10 \)
* \( y \leq 8 \)
* \( x \geq 0 \)
* \( y \geq 0 \)
2. **Graph each inequality on the coordinate plane:**
- **Inequality 1: \( x + y \geq 5 \)**
- This represents the region above or on the line \( x + y = 5 \).
- **Inequality 2: \( x \leq 10 \)**
- This represents the region to the left of or on the line \( x = 10 \).
- **Inequality 3: \( y \leq 8 \)**
- This represents the region below or on the line \( y = 8 \).
- **Inequality 4: \( x \geq 0 \)**
- This indicates the region to the right of or on the y-axis.
- **Inequality 5: \( y \geq 0 \)**
- This indicates the region above or on the x-axis.
3. **Determine the feasible region:**
- The feasible region is the intersection of the areas defined by all given inequalities.
- The points that define the corners (intersection points) of this region are the vertices.
4. **Find the vertices:**
- Set up each pair of equations to determine intersection points:
- \( x + y = 5 \) and \( x = 0 \): \( (0, 5) \)
- \( x + y = 5 \) and \( y = 0 \): \( (5, 0) \)
- \( x + y = 5 \) and \( x = 10 \): \( (10, -5) \)
- \( x + y = 5 \) and \( y = 8 \): \( (-3, 8) \)
- \( y = 8 \) and \( x = 10 \): \( (10, 8) \)
- Note that some intersection](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8bdb2115-39a3-4b83-948f-9ca4d17539c2%2F5942d2be-ab46-46da-8fb8-7b650e481e53%2Fx7p8l9s_processed.png&w=3840&q=75)
Transcribed Image Text:### Sketching the Feasible Region for Given Inequalities
To determine the region that corresponds to the given inequalities, we'll follow these steps:
1. **Identify the inequalities:**
* \( x + y \geq 5 \)
* \( x \leq 10 \)
* \( y \leq 8 \)
* \( x \geq 0 \)
* \( y \geq 0 \)
2. **Graph each inequality on the coordinate plane:**
- **Inequality 1: \( x + y \geq 5 \)**
- This represents the region above or on the line \( x + y = 5 \).
- **Inequality 2: \( x \leq 10 \)**
- This represents the region to the left of or on the line \( x = 10 \).
- **Inequality 3: \( y \leq 8 \)**
- This represents the region below or on the line \( y = 8 \).
- **Inequality 4: \( x \geq 0 \)**
- This indicates the region to the right of or on the y-axis.
- **Inequality 5: \( y \geq 0 \)**
- This indicates the region above or on the x-axis.
3. **Determine the feasible region:**
- The feasible region is the intersection of the areas defined by all given inequalities.
- The points that define the corners (intersection points) of this region are the vertices.
4. **Find the vertices:**
- Set up each pair of equations to determine intersection points:
- \( x + y = 5 \) and \( x = 0 \): \( (0, 5) \)
- \( x + y = 5 \) and \( y = 0 \): \( (5, 0) \)
- \( x + y = 5 \) and \( x = 10 \): \( (10, -5) \)
- \( x + y = 5 \) and \( y = 8 \): \( (-3, 8) \)
- \( y = 8 \) and \( x = 10 \): \( (10, 8) \)
- Note that some intersection
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