Sketch the region of integration and evaluate by changing to polar coordinates: 1/² √1-2² 6x dy dx =

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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**Text for Educational Website:**

**Problem Statement:**

Sketch the region of integration and evaluate by changing to polar coordinates:

\[
\int_{0}^{1/2} \int_{\sqrt{3x}}^{\sqrt{1-x^2}} 6x \, dy \, dx = \text{[Insert Solution]}
\]

**Explanation:**

This problem involves calculating a double integral by first sketching the given region of integration in the xy-plane and then converting the Cartesian coordinates to polar coordinates for evaluation. 

**Steps to Follow:**

1. **Identify the Region of Integration:**
   - The bounds for \(x\) are from 0 to \(\frac{1}{2}\).
   - The bounds for \(y\) depend on \(x\), going from \( \sqrt{3x} \) to \( \sqrt{1-x^2} \).

2. **Convert to Polar Coordinates:**
   - Use the transformations \(x = r\cos\theta\) and \(y = r\sin\theta\).
   - Update the integration bounds and the integrand function to reflect these transformations.

3. **Integrate:**
   - Set up the integral in terms of \(r\) and \(\theta\).
   - Evaluate the integral to find the solution.

This approach simplifies the evaluation by converting complicated regions in Cartesian coordinates to more manageable regions in polar coordinates.
Transcribed Image Text:**Text for Educational Website:** **Problem Statement:** Sketch the region of integration and evaluate by changing to polar coordinates: \[ \int_{0}^{1/2} \int_{\sqrt{3x}}^{\sqrt{1-x^2}} 6x \, dy \, dx = \text{[Insert Solution]} \] **Explanation:** This problem involves calculating a double integral by first sketching the given region of integration in the xy-plane and then converting the Cartesian coordinates to polar coordinates for evaluation. **Steps to Follow:** 1. **Identify the Region of Integration:** - The bounds for \(x\) are from 0 to \(\frac{1}{2}\). - The bounds for \(y\) depend on \(x\), going from \( \sqrt{3x} \) to \( \sqrt{1-x^2} \). 2. **Convert to Polar Coordinates:** - Use the transformations \(x = r\cos\theta\) and \(y = r\sin\theta\). - Update the integration bounds and the integrand function to reflect these transformations. 3. **Integrate:** - Set up the integral in terms of \(r\) and \(\theta\). - Evaluate the integral to find the solution. This approach simplifies the evaluation by converting complicated regions in Cartesian coordinates to more manageable regions in polar coordinates.
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