Sketch the region of integration and change the order of integration. So SN f(x, y)dyd.r f (x, y) dxdy
Sketch the region of integration and change the order of integration. So SN f(x, y)dyd.r f (x, y) dxdy
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![**Sketch the Region of Integration and Change the Order of Integration**
The given double integral is:
\[
\int_{0}^{4} \int_{0}^{\sqrt{x}} f(x, y) \, dy \, dx
\]
**Task:** Sketch the region of integration and change the order of integration.
### Explanation
The limits of integration for \( y \) are from \( 0 \) to \( \sqrt{x} \), and for \( x \) are from \( 0 \) to \( 4 \).
### Region of Integration
To visualize the region:
1. **x limits:** From 0 to 4.
2. **y limits:** From 0 to \(\sqrt{x}\).
This represents the area under the curve \( y = \sqrt{x} \) from \( x = 0 \) to \( x = 4 \).
### New Order of Integration
We need to express \( x \) as a function of \( y \) by solving \( y = \sqrt{x} \) for \( x \):
\[ x = y^2 \]
**New limits:**
- For \( x \): from \( y^2 \) to 4.
- For \( y \): from 0 to 2 (since \( \sqrt{4} = 2 \)).
This changes the order of the integral to:
\[
\int_{0}^{2} \int_{y^2}^{4} f(x, y) \, dx \, dy
\]
### Summary
The integration order is switched from \(\int \int dydx\) to \(\int \int dxdy\), with the newly determined limits reflecting the same region of integration.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F763773a4-b59e-428b-8a3f-bc3dd5fb97d6%2Fa902dd5c-523b-4933-8a8c-e0ecacb4fdfc%2Fqxdn0pv_processed.png&w=3840&q=75)
Transcribed Image Text:**Sketch the Region of Integration and Change the Order of Integration**
The given double integral is:
\[
\int_{0}^{4} \int_{0}^{\sqrt{x}} f(x, y) \, dy \, dx
\]
**Task:** Sketch the region of integration and change the order of integration.
### Explanation
The limits of integration for \( y \) are from \( 0 \) to \( \sqrt{x} \), and for \( x \) are from \( 0 \) to \( 4 \).
### Region of Integration
To visualize the region:
1. **x limits:** From 0 to 4.
2. **y limits:** From 0 to \(\sqrt{x}\).
This represents the area under the curve \( y = \sqrt{x} \) from \( x = 0 \) to \( x = 4 \).
### New Order of Integration
We need to express \( x \) as a function of \( y \) by solving \( y = \sqrt{x} \) for \( x \):
\[ x = y^2 \]
**New limits:**
- For \( x \): from \( y^2 \) to 4.
- For \( y \): from 0 to 2 (since \( \sqrt{4} = 2 \)).
This changes the order of the integral to:
\[
\int_{0}^{2} \int_{y^2}^{4} f(x, y) \, dx \, dy
\]
### Summary
The integration order is switched from \(\int \int dydx\) to \(\int \int dxdy\), with the newly determined limits reflecting the same region of integration.
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