Sketch the region enclosed by the given curves. Decide whether to integrate with respect to x or y. Then find the area of the region. 2y = 3√x, y = 5, and 2y + 2x = 5 -7.47 X

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Question
**Problem Statement**

Sketch the region enclosed by the given curves. Decide whether to integrate with respect to \( x \) or \( y \). Then find the area of the region.

Given Equations:
- \( 2y = 3\sqrt{x} \)
- \( y = 5 \)
- \( 2y + 2x = 5 \)

**Solution Attempt**

The answer provided: \(-7.47\) is incorrect. 

*Explanation and Steps*

1. **Graphing the Curves**:
   - **Equation 1**: Rearrange \(2y = 3\sqrt{x}\) to express \(y\) in terms of \(x\):
     \[
     y = \frac{3}{2}\sqrt{x}
     \]
     This is a square root function, which starts at the origin and increases to the right.

   - **Equation 2**: The equation \(y = 5\) is a horizontal line across \(y = 5\).

   - **Equation 3**: Rearrange \(2y + 2x = 5\) to express \(y\):
     \[
     y = -x + \frac{5}{2}
     \]
     This is a straight line with a negative slope.

2. **Decide Integration Method**:
   - Identify where the curves intersect and the regions they enclose. This will guide whether to integrate with respect to \( x \) or \( y \). Set up the integrals to find the exact area of the enclosed region by calculating intersections and the enclosed area.

*Note: Make sure calculations yield a positive area value.*
Transcribed Image Text:**Problem Statement** Sketch the region enclosed by the given curves. Decide whether to integrate with respect to \( x \) or \( y \). Then find the area of the region. Given Equations: - \( 2y = 3\sqrt{x} \) - \( y = 5 \) - \( 2y + 2x = 5 \) **Solution Attempt** The answer provided: \(-7.47\) is incorrect. *Explanation and Steps* 1. **Graphing the Curves**: - **Equation 1**: Rearrange \(2y = 3\sqrt{x}\) to express \(y\) in terms of \(x\): \[ y = \frac{3}{2}\sqrt{x} \] This is a square root function, which starts at the origin and increases to the right. - **Equation 2**: The equation \(y = 5\) is a horizontal line across \(y = 5\). - **Equation 3**: Rearrange \(2y + 2x = 5\) to express \(y\): \[ y = -x + \frac{5}{2} \] This is a straight line with a negative slope. 2. **Decide Integration Method**: - Identify where the curves intersect and the regions they enclose. This will guide whether to integrate with respect to \( x \) or \( y \). Set up the integrals to find the exact area of the enclosed region by calculating intersections and the enclosed area. *Note: Make sure calculations yield a positive area value.*
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