Sketch the graph of the function f. f(x) = −2x + 4 if x < 1 3 if x = 1 x2 + 1 if x > 1 The x y-coordinate plane is given. A function with 3 parts is graphed. The first part is linear, enters the window in the third quadrant, goes up and right, crosses the y-axis at y = −4, and ends at the open point (1, −2). The second part is the point (1, 3). The third part is a curve, begins at the open point (1, 2), goes up and right becoming more steep, passes through the point (2, 5), and exits the window in the first quadrant. The x y-coordinate plane is given. A function with 3 parts is graphed. The first part is linear, enters the window in the second quadrant, goes down and right, crosses the y-axis at y = 4, and ends at the open point (1, 2). The second part is the point (1, 3). The third part is a curve, begins at the open point (1, 2), goes up and right becoming more steep, passes through the point (2, 5), and exits the window in the first quadrant. The x y-coordinate plane is given. A function with 3 parts is graphed. The first part is linear, enters the window in the second quadrant, goes down and right, crosses the y-axis at y = 4, and ends at the open point (1, 2). The second part is the point (1, 3). The third part is a curve, begins at the open point (1, −2), goes down and right becoming more steep, passes through the point (2, −5), and exits the window in the fourth quadrant. The x y-coordinate plane is given. A function with 3 parts is graphed. The first part is linear, enters the window in the third quadrant, goes up and right, crosses the y-axis at y = −4, and ends at the open point (1, −2). The second part is the point (1, 3). The third part is a curve, begins at the open point (1, −2), goes down and right becoming more steep, passes through the point (2, −5), and exits the window in the fourth quadrant. Evaluate given a = 1. (If an answer does not exist, enter DNE.) lim x→a f(x)
Sketch the graph of the function f. f(x) = −2x + 4 if x < 1 3 if x = 1 x2 + 1 if x > 1 The x y-coordinate plane is given. A function with 3 parts is graphed. The first part is linear, enters the window in the third quadrant, goes up and right, crosses the y-axis at y = −4, and ends at the open point (1, −2). The second part is the point (1, 3). The third part is a curve, begins at the open point (1, 2), goes up and right becoming more steep, passes through the point (2, 5), and exits the window in the first quadrant. The x y-coordinate plane is given. A function with 3 parts is graphed. The first part is linear, enters the window in the second quadrant, goes down and right, crosses the y-axis at y = 4, and ends at the open point (1, 2). The second part is the point (1, 3). The third part is a curve, begins at the open point (1, 2), goes up and right becoming more steep, passes through the point (2, 5), and exits the window in the first quadrant. The x y-coordinate plane is given. A function with 3 parts is graphed. The first part is linear, enters the window in the second quadrant, goes down and right, crosses the y-axis at y = 4, and ends at the open point (1, 2). The second part is the point (1, 3). The third part is a curve, begins at the open point (1, −2), goes down and right becoming more steep, passes through the point (2, −5), and exits the window in the fourth quadrant. The x y-coordinate plane is given. A function with 3 parts is graphed. The first part is linear, enters the window in the third quadrant, goes up and right, crosses the y-axis at y = −4, and ends at the open point (1, −2). The second part is the point (1, 3). The third part is a curve, begins at the open point (1, −2), goes down and right becoming more steep, passes through the point (2, −5), and exits the window in the fourth quadrant. Evaluate given a = 1. (If an answer does not exist, enter DNE.) lim x→a f(x)
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
Sketch the graph of the function f.
f(x) =
−2x + 4 | if x < 1 | |
3 | if x = 1 | |
x2 + 1 | if x > 1 |
The x y-coordinate plane is given. A function with 3 parts is graphed.
- The first part is linear, enters the window in the third quadrant, goes up and right, crosses the y-axis at y = −4, and ends at the open point (1, −2).
- The second part is the point (1, 3).
- The third part is a curve, begins at the open point (1, 2), goes up and right becoming more steep, passes through the point (2, 5), and exits the window in the first quadrant.
The x y-coordinate plane is given. A function with 3 parts is graphed.
- The first part is linear, enters the window in the second quadrant, goes down and right, crosses the y-axis at y = 4, and ends at the open point (1, 2).
- The second part is the point (1, 3).
- The third part is a curve, begins at the open point (1, 2), goes up and right becoming more steep, passes through the point (2, 5), and exits the window in the first quadrant.
The x y-coordinate plane is given. A function with 3 parts is graphed.
- The first part is linear, enters the window in the second quadrant, goes down and right, crosses the y-axis at y = 4, and ends at the open point (1, 2).
- The second part is the point (1, 3).
- The third part is a curve, begins at the open point (1, −2), goes down and right becoming more steep, passes through the point (2, −5), and exits the window in the fourth quadrant.
The x y-coordinate plane is given. A function with 3 parts is graphed.
- The first part is linear, enters the window in the third quadrant, goes up and right, crosses the y-axis at y = −4, and ends at the open point (1, −2).
- The second part is the point (1, 3).
- The third part is a curve, begins at the open point (1, −2), goes down and right becoming more steep, passes through the point (2, −5), and exits the window in the fourth quadrant.
Evaluate given a = 1. (If an answer does not exist, enter DNE.)
lim x→a f(x)
![Sketch the graph of the function f.
-2x + 4
if x < 1
f(x) =
if x = 1
2
x + 1
if x > 1](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F75750e15-f2b0-4135-a3c1-2da1dff37f84%2F24397437-4573-43c0-8b9a-8847da716087%2Fl8mfarp_processed.png&w=3840&q=75)
Transcribed Image Text:Sketch the graph of the function f.
-2x + 4
if x < 1
f(x) =
if x = 1
2
x + 1
if x > 1
![Evaluate given a =
1. (If an answer does not exist, enter DNE.)
lim f(x)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F75750e15-f2b0-4135-a3c1-2da1dff37f84%2F24397437-4573-43c0-8b9a-8847da716087%2F472e6t_processed.png&w=3840&q=75)
Transcribed Image Text:Evaluate given a =
1. (If an answer does not exist, enter DNE.)
lim f(x)
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