Sketch the graph of a single function f(x) that satisfies all of the following conditions, labeling all local extrema, inflection points, and asymptotes. Afterwards, explicitly state the intervals of increase, decrease, and concavity. • The domain of f(x) is (-∞, ∞) ƒ'(x) = 5x²(x² − 3) f"(x) = 10x (2x² – 3) ● ● f(0) = 0

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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### Educational Resource: Graphing Functions with Specific Conditions

#### Task Description:
Sketch the graph of a single function \( f(x) \) that satisfies all of the following conditions, labeling all local extrema, inflection points, and asymptotes.

#### Steps to Follow:
1. **Identify Key Features**:
   - **Local Extrema**: Points where the function changes from increasing to decreasing or vice versa.
   - **Inflection Points**: Points where the concavity of the function changes.
   - **Asymptotes**: Lines that the graph approaches but does not touch.

2. **Explicitly State the Intervals**:
   - Intervals of increase and decrease.
   - Intervals of concavity.

### Given Conditions:
1. **The domain of \( f(x) \)** is \( (-\infty, \infty) \).
2. The first derivative of the function is given by:
   \[
   f'(x) = 5x^2(x^2 - 3)
   \]
3. The second derivative of the function is given by:
   \[
   f''(x) = 10x(2x^2 - 3)
   \]
4. The function passes through the point:
   \[
   f(0) = 0
   \]

### Analysis of Given Conditions:
- **First Derivative \( f'(x) \)**:
  - Determines the slope of the function \( f(x) \).
  - Critical points are found by setting \( f'(x) = 0 \):
    \[
    5x^2(x^2 - 3) = 0
    \]
    Solutions: \( x = 0, \pm\sqrt{3} \)

- **Second Derivative \( f''(x) \)**:
  - Determines the concavity of the function \( f(x) \).
  - Possible inflection points are found by setting \( f''(x) = 0 \):
    \[
    10x(2x^2 - 3) = 0
    \]
    Solutions: \( x = 0, \pm\sqrt{\frac{3}{2}} \)

### Graphing Instructions:
- **Plot the Critical Points**:
  - At \( x = 0, \pm\sqrt{3} \)

- **Determine Intervals of Increase
Transcribed Image Text:### Educational Resource: Graphing Functions with Specific Conditions #### Task Description: Sketch the graph of a single function \( f(x) \) that satisfies all of the following conditions, labeling all local extrema, inflection points, and asymptotes. #### Steps to Follow: 1. **Identify Key Features**: - **Local Extrema**: Points where the function changes from increasing to decreasing or vice versa. - **Inflection Points**: Points where the concavity of the function changes. - **Asymptotes**: Lines that the graph approaches but does not touch. 2. **Explicitly State the Intervals**: - Intervals of increase and decrease. - Intervals of concavity. ### Given Conditions: 1. **The domain of \( f(x) \)** is \( (-\infty, \infty) \). 2. The first derivative of the function is given by: \[ f'(x) = 5x^2(x^2 - 3) \] 3. The second derivative of the function is given by: \[ f''(x) = 10x(2x^2 - 3) \] 4. The function passes through the point: \[ f(0) = 0 \] ### Analysis of Given Conditions: - **First Derivative \( f'(x) \)**: - Determines the slope of the function \( f(x) \). - Critical points are found by setting \( f'(x) = 0 \): \[ 5x^2(x^2 - 3) = 0 \] Solutions: \( x = 0, \pm\sqrt{3} \) - **Second Derivative \( f''(x) \)**: - Determines the concavity of the function \( f(x) \). - Possible inflection points are found by setting \( f''(x) = 0 \): \[ 10x(2x^2 - 3) = 0 \] Solutions: \( x = 0, \pm\sqrt{\frac{3}{2}} \) ### Graphing Instructions: - **Plot the Critical Points**: - At \( x = 0, \pm\sqrt{3} \) - **Determine Intervals of Increase
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