Sketch a potential energy diagram for the decomposition of nitrous oxide. N20(9) → N2 (9) + O(9) The activation energy for the forward reaction is 269 kJ; AH® is +167 kJ. What is the activation energy for the reverse reaction? Activation energy =| |kJ
Sketch a potential energy diagram for the decomposition of nitrous oxide. N20(9) → N2 (9) + O(9) The activation energy for the forward reaction is 269 kJ; AH® is +167 kJ. What is the activation energy for the reverse reaction? Activation energy =| |kJ
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Title: Understanding Potential Energy Diagrams in Chemical Reactions**
**Potential Energy Diagram for the Decomposition of Nitrous Oxide:**
**Chemical Equation:**
\[ \text{N}_2\text{O (g)} \rightarrow \text{N}_2\text{(g)} + \text{O(g)} \]
In this decomposition reaction, nitrous oxide (\( \text{N}_2\text{O} \)) breaks down into nitrogen (\( \text{N}_2 \)) and oxygen (\( \text{O} \)) gases.
**Activation Energy:**
- The activation energy for the forward reaction is 269 kJ.
- The change in enthalpy (\( \Delta H^\circ \)) for the reaction is +167 kJ.
To find the activation energy for the reverse reaction, use the relationship:
\[ \text{Activation Energy (reverse)} = \text{Activation Energy (forward)} - \Delta H^\circ \]
**Calculation:**
\[ \text{Activation Energy (reverse)} = 269 \, \text{kJ} - 167 \, \text{kJ} = 102 \, \text{kJ} \]
Therefore, the activation energy for the reverse reaction is 102 kJ.
**Educational Insight:**
Potential energy diagrams provide a visual representation of the energy changes during a chemical reaction. The peaks represent the activation energy needed to initiate the reaction, while the difference in energy between reactants and products represents the enthalpy change (\( \Delta H \)). Understanding these concepts is crucial for analyzing reaction dynamics and kinetics in chemistry.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F97e1b17f-72c5-4bfa-9560-03b6b866a058%2F512d735e-e1c8-4aac-9006-d9dd4289bcde%2F6t7lzh_processed.png&w=3840&q=75)
Transcribed Image Text:**Title: Understanding Potential Energy Diagrams in Chemical Reactions**
**Potential Energy Diagram for the Decomposition of Nitrous Oxide:**
**Chemical Equation:**
\[ \text{N}_2\text{O (g)} \rightarrow \text{N}_2\text{(g)} + \text{O(g)} \]
In this decomposition reaction, nitrous oxide (\( \text{N}_2\text{O} \)) breaks down into nitrogen (\( \text{N}_2 \)) and oxygen (\( \text{O} \)) gases.
**Activation Energy:**
- The activation energy for the forward reaction is 269 kJ.
- The change in enthalpy (\( \Delta H^\circ \)) for the reaction is +167 kJ.
To find the activation energy for the reverse reaction, use the relationship:
\[ \text{Activation Energy (reverse)} = \text{Activation Energy (forward)} - \Delta H^\circ \]
**Calculation:**
\[ \text{Activation Energy (reverse)} = 269 \, \text{kJ} - 167 \, \text{kJ} = 102 \, \text{kJ} \]
Therefore, the activation energy for the reverse reaction is 102 kJ.
**Educational Insight:**
Potential energy diagrams provide a visual representation of the energy changes during a chemical reaction. The peaks represent the activation energy needed to initiate the reaction, while the difference in energy between reactants and products represents the enthalpy change (\( \Delta H \)). Understanding these concepts is crucial for analyzing reaction dynamics and kinetics in chemistry.
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