33. A trouser manufacturer has an order for 80,000men's trousers in a normal distribution of waistsizes 28, 30, 32, 34, 36, 38, 40, 42, and 44, with amean of 36, and a sample standard deviation of2.1. Find the number of trousers to be made ofeach waist size. (Use the empirical rule.)a.How many trousers should be made withinone standard deviation of the mean?What waist sizes are included in this set?(Circle all that apply.)28 30 32 34 36 38 40 42 44b. How many trousers should be madebetween one and two standard deviation ofthe mean?What waist sizes are included in this set?(Circle all that apply.)28 30 32 34 36 38 40 42 44How many trousers should be madebetween two and three standardС.deviation of the mean?What waist sizes are included in this set?(Circle all that apply.)28 30 32 34 36 38 40 42 44

According to the empirical rule 68% of the data lie within 1 standard deviation of the mean Thus, number of waist size that will be within one the standard deviation of the mean will be: expected number = probability ×number of trousers =0.68×80000 =54400 Therefore the required number of orders are 54400 The 1 standard deviation of the mean limit can be calculated as: Thus, waist size between these limited will be circled which are 34,36,38According to empirical rule 99.7% of the data lie within 3 standard deviation of the mean . So the 99.7%-95% = 4.7% of the data lie within 2 and 3 standard deviation of the mean . Thus, number of waist size that will be within one and two the standard deviation of the mean will be: expected number = probability ×number of trousers =0.27×80000 =21600 Therefore the required number of orders are 21600 The 2 standard deviation of the mean limit can be calculated as: Any thing that does not fall in this range (33.9, 38.1) but lie within this range of (31.8, 40.2) Thus, waist size between these limited will be circled which are 32, 40According to empirical rule 95% of the data lie within 2 standard deviation of the mean . So the 95%-68% = 27% of the data lie within 1 and two standard deviation of the mean . Thus, number of waist size that will be within one and two the standard deviation of the mean will be: expected number = probability ×number of trousers =0.047×80000 =3760 Therefore the required number of orders are 3760 The 3 standard deviation of the mean limit can be calculated as: Any thing that does not fall in this range (31.8, 40.2) but lie within this range of (29.7, 42.3) Thus, waist size between these limited will be circled which are 30, 42

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sizes 28, 30, 32, 34, 36, 38, 40, 42, and 44, with a mean of 36, and a sample standard deviation of 2.1. Find the number of trousers to be made of each waist size. (Use the empirical rule.) How many trousers should be made within one standard deviation of the mean? a.

sizes 28, 30, 32, 34, 36, 38, 40, 42, and 44, with a mean of 36, and a sample standard deviation of 2.1. Find the number of trousers to be made of each waist size. (Use the empirical rule.) How many trousers should be made within one standard deviation of the mean? a.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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