Sixty percent of U.S. mothers with school-age children choose fast-food as a dining option for their families one to three times a week. You randomly select five U.S. mothers with school-age children and ask them whether they choose fast-food as a dining option for their families one to three times a week. The random value represents the number of mothers who choose fast food one to three times a week.  Calculate the probability that two mothers in your sample choose fast food once to three times a week.     Using the table determine the probability that more than two mothers choose fast food once to three times a week.     What is the mean of this distribution?       What is the standard deviation?

Q: From experience, an airline knows that only 85% of the passengers booked for a certain flight…

A: Given Information :  From experience, an airline knows that only 85% of the passengers booked for a…

Q: Find the odds in favor of an event and odds against event S.  For Samsung ships 23.5 percent of the…

A: A: Samsung shipsP(A)=23.5%=0.235P(Ac)=1-P(A)=1-0.235=0.765

Q: D. Based on the ercent chance of

A: The event A and event B are the mutually exclusive events , they are not the dependent events which…

Q: Twenty-four percent of couples who plan to marry this year are planning destination weddings. In a…

A: I solved exactly first 3 subpart because of bartleby policy....   Let random variable X: number of…

Q: If 25 percent of students at a particular school use mechanical pencils, what is the probability of…

A: Given Information: The percentage of students using mechanical pencils =25% Number of the sample…

Q: The probability that at least 1 freshman is chosen for the committee is ?

A: Let p be the proportion of freshmen. Given that p = 29% = 0.29 Also, X denotes number of freshmen on…

Q: Marketers find that 87% of US teenagers use the Internet. Consider a random sample over 282 US…

A:

Q: In one study, researchers at a clinic looked at more than 120,000 patients enrolled in 14…

A: Given Information:  Researchers at a clinic looked at more than 120,000 patients enrolled in 14…

Q: A zoo has a collection of 400 flamingos. 180 of these flamingos are red. One day, a fence blew down…

A: Given : A zoo has a collection of 400 flamingos. 180 of these flamingos are red.

Q: In a management trainee programme, women make up 80% of the participants, while males make up 20%.…

A:

Q: randomly pick 10 such

A: Let X be the random variable such that number of institutions offering online courses. N: Total…

Q: The proportion of eligible voters in the next election who will vote for the incumbent is assumed to…

A: Given: The probability of eligible voters in the next election who will vote for the incumbent is…

Q: In a Survey, 85% of the people interviewed were unaware that maintaining a healthy weight could…

A: Givenp=0.85n=20Let "x" be the no.of people are unware that maintaining a healthy weightcould reduce…

Q: If the probability of choosing a red chip from a bucket is 0.4, What is the probability of not…

A: We have the probability of choosing a red chip from a bucket is 0.4

Q: 2002, approximately 39% of the people eligible to vote in mid-term elections voted. Suppose you have…

A: the number of trials n=7the number of successes x=0the probability of success on a single trial…

Q: According to Gallup poll, 36% of all college students use an Apple i phone only.  If a sample of 200…

A: 1. Consider that p is population proportion of all college students who use an Apple i phone.

Q: In Wyoming, there are about 300,000 registered voters, of whom 30,000 are Democrats. A survey…

A: Given that  N=300000 , X=30000 , n=900 p=X/N=30000/300000=0.10

Q: Suppose the budget has the support of 54​% of the voters. What is the probability that the​…

A: The proportion of population in support follows normal distribution with mean 0.53 and standard…

Q: Twenty percent of all undergraduates at a university are chemistry majors. In a random sample of…

A: Given information:Population proportion (p) = 20%                                         p =…

Q: 42% of US adults have very little confidence in newspapers. You randomly select 10 US adults. Find…

A: Given that, 42% of US adults have very little confidence in newspapers. Sample size, n = 10

Q: Suppose a recent study determined that 29% of Americans favorite ice cream flavor is If a sample of…

A:

Q: A student has a 30% chance of getting a particular professor for a class. What are the odds of…

A: From the provided information, There is 30% chance a student getting a particular professor for a…

Q: In a survey of consumers aged 12 and​ older, respondents were asked how many cell phones were in use…

A: Given: Number of respondents answered none = 208 Number of respondents answered one = 295 Number of…

Q: The proportion of eligible voters in the next election who will vote for the incumbent is assumed to…

A: Given information- Sample size, n = 510 The proportion of eligible voters = 0.54 Now, from Binomial…

Q: The USDA reports that 31% of four-member households spend less than $100 per week on groceries.…

A: Given p=31%=0.31 n=600 Here, the sample size is large. Hence, we can use normal approximation.…

Q: Just before a referendum on a school​ budget, a local newspaper polls 357 voters to predict whether…

A: Given, n = 357 p = 53% = 0.53

Q: Approximately 10.3% of high school students drop out of school before graduation. From a random…

A: Let p be the probability of high school students drop out of school before graduation  n=Sample  X…

Q: In a survey of consumers aged 12 and​ older, respondents were asked how many cell phones were in use…

A:

Q: three out of four university students under 25 years old have eaten eggs for breakfast. If a random…

A: Solution: Given data: Probability, P = 3/4  = 0.75 Sample size (n) = 20 To find : the probability…

Q: In 2002, approximately 39% of the people eligible to vote in mid-term elections voted. Suppose you…

A: Number of trials n=7Success of probability p=0.39X~binomial (n,p)nCx=n!/x!(n-x)!Probability mass…

Q: In the fall of 2003, a magazine article reported that about 87% of adults drink milk. A local dairy…

A: Let X be the random variable for the number of people who said that they drink milk. The population…

Q: 200 volunteers at a local kennel were surveyed. It was found that 132 women and 68 men volunteered.…

A: given data  132 women 68 men _______________ 200 total surveyed   of the 132 women 91 liked dogs and…

Q: In a sample of 1500 adult U.S. citizens, 690 said that Donald Trump was the worst president in U.S.…

A: Sample of size(n)=1500X=no.of adults who said Donald trump was the worst president in…

Q: According to the Center for Disease Control (CDC), the percentage of boys who are diagnosed with…

A:

Q: An airline estimates that 6% of people booked on their flights do not show up. If the airline books…

A: Let X be the random variable from binomial distribution with probability of will not show up (q)= 6%…

Q: 2016, 75.8% of women aged 20-24 had no children. What is the chance that if you wanted to meet a…

A: Given that : In 2016, 75.8% of women aged 20-24 had no children.  What is the chance that if you…

Q: In one Introductory Statistics class, the probability that a student will pass the first test is…

A: events: A: pass first test  B: pass second test   P(A) = 0.55         P(A') = 1 - 0.55 = 0.45 P(B|A)…

Q: The number of death due to diabetes and kidney disease for an American during 2015 is respectively…

A: The number of death due to diabetes and kidney disease for an American during 2015 is respectively…

Q: A professor surveyed his students and asked whether the students love business statistics. One…

A: Given,sample size(n)=100sample proportion(p^)=0.59

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.