Sixty gym members were randomly selected and their weights were recorded and inputted into MINITAB. The results are summarized in Exhibit 1 below. One-Sample Z: Weight Test of mu = 195 vs < 195 The assumed standard deviation = 22.11 Variable  N    Mean    StDev     SE Mean Weight   60   193.13   22.11         ? 1.Calculate the p-value for this test and State the conclusion of this test, giving a reason for your answer.

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Q: Sixty gym members were randomly selected and their weights were recorded and inputted into MINITAB.…

A: Given that, Sample size n=60 Sample mean x¯=193.13 Population standard deviation σ=22.11

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Q: Sixty gym members were randomly selected and their weights were recorded and inputted into MINITAB.…

A: Given : X¯ =193.13 σ = 22.11 n = 60 Hypothesis : H0:μ = 195  H1:μ &lt; 195

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Q: Sixty gym members were randomly selected and their weights were recorded and inputted into MINITAB.…

A: Given : Hypothesis : H0 : μ = 195 H1 : μ &lt; 195 x¯ = 193.13 σ = 22.11 n = 60 SE Mean = 22.1160 SE…

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Q: Sixty gym members were randomly selected and their weights were recorded and inputted into MINITAB.…

A: Sample size n = 60 Sample mean x = 193.13 Standard deviation σ = 22.11 Null hypothesis H0:  Mean…

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