Six balls numbered 1 to 6 are placed in a bag. Some of the balls are grey and some are white. The balls numbered 2 and 5 are grey. The balls numbered 1, 3, 4, and 6 are white. A ball will be selected from the bag at random. The 6 possible outcomes are listed below. Note that each outcome has the same probability. 6. Complete parts (a) through (c). Write the probabilities as fractions. (a) Check the outcomes for each event below. Then, enter the probability of the event. Outcomes Probability 6. 1 3 4 Event A: The selected ball is white Event B: The seiected ball has an even number on it Event A and B: The selected ball is white and has an even number on it Event A or B: The selected ball is white or has an even number on it (b) Compute the following. P(A) + P(B) – P(A and B) = 0 olo lo

College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter8: Sequences, Series, And Probability
Section8.CR: Chapter Review
Problem 80E
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29.
Six balls numbered 1 to 6 are placed in a bag.
Some of the balls are grey and some are white.
The balls numbered 2 and 5 are grey. The balls numbered 1, 3, 4, and 6 are white.
A ball will be selected from the bag at random.
The 6 possible outcomes are listed below.
Note that each outcome has the same probability.
6.
Complete parts (a) through (c). Write the probabilities as fractions.
(a) Check the outcomes for each event below. Then, enter the probability of the event.
Outcomes
Probability
6.
1
4
Event A: The selected ball is white
Event B: The seiected ball has an even number on it
Event A and B: The selected ball is white and has an even number on it
Event A or B: The selected ball is white or has an even number on it
(b) Compute the following.
P(A) + P(B) - P(A and B) = ]
Transcribed Image Text:Six balls numbered 1 to 6 are placed in a bag. Some of the balls are grey and some are white. The balls numbered 2 and 5 are grey. The balls numbered 1, 3, 4, and 6 are white. A ball will be selected from the bag at random. The 6 possible outcomes are listed below. Note that each outcome has the same probability. 6. Complete parts (a) through (c). Write the probabilities as fractions. (a) Check the outcomes for each event below. Then, enter the probability of the event. Outcomes Probability 6. 1 4 Event A: The selected ball is white Event B: The seiected ball has an even number on it Event A and B: The selected ball is white and has an even number on it Event A or B: The selected ball is white or has an even number on it (b) Compute the following. P(A) + P(B) - P(A and B) = ]
Event A and B: The selected ball is white and has an even number on it
Event A or B: The selected ball is white or has an even number on it
(b) Compute the following.
P(A) + P(B) – P(A and B) = 0
%3D
(c) Select the answer that makes the equation true
P(A)+P(B)-P(A and B)= (Choose one)
%3D
Transcribed Image Text:Event A and B: The selected ball is white and has an even number on it Event A or B: The selected ball is white or has an even number on it (b) Compute the following. P(A) + P(B) – P(A and B) = 0 %3D (c) Select the answer that makes the equation true P(A)+P(B)-P(A and B)= (Choose one) %3D
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